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我已經看到多個帖子,但由於某些原因,我嘗試返回一個空的XmlNodeList。我錯過了什麼?使用XPath選擇XMLNode
我的XML:
<string xmlns='http://ws.jobboard.com/resumes/'>
<Packet>
<Errors />
<PageNumber>1</PageNumber>
<SearchTime>02/25/2014 10:11:47</SearchTime>
<FirstRec>1</FirstRec>
<LastRec>100</LastRec>
<Hits>206816</Hits>
<MaxPage>40</MaxPage>
<Results>
<ResumeResultItem_V3>
<ContactEmail></ContactEmail>
<ContactName>Lisa Yada</ContactName>
<HomeLocation>US-CO-Lakewood</HomeLocation>
<LastUpdate>2014/2/24</LastUpdate>
<ResumeTitle>Web Design & Developement</ResumeTitle>
<JobTitle>Web Design & Developement</JobTitle>
<RecentEmployer>Some Company</RecentEmployer>
<RecentJobTitle>Web Design</RecentJobTitle>
<RecentPay>0</RecentPay>
<ResumeID>RHV47X78Z5CN56</ResumeID>
<UserDID>UHT6R86LL8C581</UserDID>
<ContactEmailMD5>93ce261b843f58962f9</ContactEmailMD5>
<ActionType />
<HighestDegree>Bachelor's Degree</HighestDegree>
<MonthsOfExperience>40</MonthsOfExperience>
<LastActivity>2/24/2014 1:22:19 PM</LastActivity>
</ResumeResultItem_V3> ...
和我的代碼:
XmlDocument jobsdoc = new XmlDocument();
jobsdoc.LoadXml(xmlstring);
XmlNodeList xnList = jobsdoc.SelectNodes("/string/Packet/Results/ResumeResultItem_V3");
foreach (XmlNode xn in xnList)
{
DataRow dr = table.NewRow();
dr["ContactName"] = xn["ContactName"].InnerText;
dr["ResumeTitle"] = xn["ResumeTitle"].InnerText;
...
table.Rows.Add(dr);
}
return table;
我已經嘗試的 「/串/包/業績/ ResumeResultItem_V3」 許多變化都無濟於事。 ws是第三方,所以我無法控制XML的格式。提前Thanx。