如何編寫選擇查詢集合匹配

Question

請幫我解決問題的想法。 我不能去想子查詢

SELECT名稱從客戶那裏assest_id IN（？子查詢？）

Answer 1

對於第一問題

select name from client where asset_id in(
select asset_id from client_asset where 
asset_desc='2' 
intersect 
select asset_id from client_asset where 
asset_id not in (select asset_id from client_asset where 
       asset_name not in ('apartment','byke'))); 

對於第一個問題首先我已經用2room提取了asset_id，用intersected提取了只有byke and apartmenta的asset_id他們的資產。這是作爲子查詢中被圍堵的語句來獲取asset_id

對於第二個問題

select name from client where asset_id in 
(select asset_id from client_asset where 
asset_desc>='2' and asset_name='apartment' 
intersect 
select asset_id from client_asset where 
asset_name='car'); 

這個查詢是自explainatory和作品以類似理由