如何處理Php中的MySQL外鍵錯誤？

我在MySQL中測試外鍵。目標是防止id輸入table2，這在table1中不存在。我希望使用foreign keys只會導致一行沒有被插入，但它似乎拋出了這個巨大的錯誤。我如何在PHP中處理這個問題？有沒有辦法讓MySQL不插入行並返回沒有行返回？如何處理Php中的MySQL外鍵錯誤？

Fatal error: Uncaught exception 'PDOException' with message 'SQLSTATE[23000]: Integrity constraint violation: 1452 Cannot add or update a child row: a foreign key constraint fails (wp-db . borrowed , CONSTRAINT borrowed_ibfk_1 FOREIGN KEY (employeeid) REFERENCES employee (id) ON DELETE CASCADE ON UPDATE CASCADE)' in C:\web\apache\htdocs\dev\foreign.php:10

Stack trace:

#0 C:\web\apache\htdocs\dev\foreign.php(10): PDOStatement->execute()

#1 {main} thrown in C:\web\apache\htdocs\dev\foreign.php on line 10

來源

2013-08-30 Norman

使用嘗試捕捉

try { 
    $pdo->exec ("QUERY WITH SYNTAX ERROR"); 
} catch (PDOException $e) { 
    if ($e->getCode() == '23000') 
     echo "Syntax Error: ".$e->getMessage(); 
}

讀PDOStatement::errorCode

從Return Code list採取

The SQL-92 standard defines a set of SQLSTATE return codes. SQLSTATE is defined as a five-character string, where the leftmost two characters define the error class, and the remaining three characters define the error subclass. Some database vendors may extend these return codes; classes beginning with the numbers 5 through 9 and letters I through Z are reserved for such implementation-specific extensions. The SQLSTATE code for a particular JDBC action can be retrieved via the getSQLState() method of SQLException

來源

2013-08-30 06:09:23 diEcho

如何處理Php中的MySQL外鍵錯誤？

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