SQL排序問題

Question

我想要檢索表中的所有值，按字母順序排序並將「全部」附加到頂部（全部不在表格中）。

當前代碼：

SELECT 0 AS TypeID, 'All' AS [Type] 
UNION 
SELECT TypeID, [Type] FROM tbl_Type ORDER BY 2 

此訂單的一切，包括所有的，這是有問題的，因爲我在這臺所謂的「協議」，這之後的排序顯示了之前所有的值。

有沒有什麼辦法可以返回一個列表頂部的「全部」和其下的所有東西？

UPDATE：

我試圖通過Andomar和康拉德建議的解決方案，但是我得到以下錯誤：

Msg 207, Level 16, State 1, Line 4 
Invalid column name 'Type'. 
Msg 104, Level 16, State 1, Line 4 
ORDER BY items must appear in the select list if the statement contains a UNION, INTERSECT or EXCEPT operator. 

Answer 1

你可以使用case排序'全部'前面：

SELECT 0 AS TypeID, 'All' AS [Type] 
UNION 
SELECT TypeID, [Type] FROM tbl_Type 
ORDER BY case when Type = 'All' then 1 else 2 end, Type 

編輯：根據您的評論，SQL Server不允許order by別名。使用子查詢：

SELECT * 
FROM (
     SELECT 0 AS TypeID, 'All' AS [Type] 
     UNION 
     SELECT TypeID, [Type] FROM tbl_Type 
     ) as SubQueryAlias 
ORDER BY case when Type = 'All' then 1 else 2 end, Type 

或在這種情況下，因爲類型是一個實際的表中的字段，而不是一個別名，交換聯盟的兩個部分：

SELECT TypeID, [Type] FROM tbl_Type 
UNION 
SELECT 0 AS TypeID, 'All' AS [Type] 
ORDER BY case when Type = 'All' then 1 else 2 end, Type 

Answer 2

隨着Andomar的答案，你也可以做到這一點來解決別名問題。

WITH CTE As 
(

    SELECT 0 AS TypeID, 'All' AS [Type] 
    UNION 
    SELECT TypeID, [Type] FROM tbl_Type 
    ORDER BY 
) 
SELECT 
    typeID, 
    Type, 
FROM 
     CTE 
ORDER BY 
    CASE 
     WHEN TypeID = 0 THEN typeID 
     ELSE Type 
    END 

但這種假設tbl_type.type的所有值都大於0

你也可以添加其他字段的CTE

WITH CTE As 
(

    SELECT 0 AS TypeID, 'All' AS [Type], 1 as sortorder 
    UNION 
    SELECT TypeID, [Type] FROM tbl_Type, 2 as sortorder 
    ORDER BY 
) 
SELECT 
    typeID, 
    Type, 
FROM 
     CTE 
ORDER BY 
    sortorder, 
    type 

Answer 3

SELECT 0 AS TypeID, 'All' AS [Type] UNION SELECT TypeID, [Type] FROM tbl_Type ORDER BY 2 DESC 

Answer 4

你可以只添加第三列進行排序，其指示它是否是一個數據記錄（或 「全部」）

SELECT 0 AS TYPEID， '全部' AS [類型]，0 AS IsDataRecord UNION SELECT TYPEID，[類型]，1 AS IsDataRecord FROM tbl_Type ORDER BY 3， 2