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使用下面的SQL語句,我可以根據需要獲得有關學生的所有信息,除了一個問題是重複記錄時,實際上每個學生只需輸入記錄。如何在多個表中使用mssql中的distinct?
Student ID Year level Semester 20012-000001 20012-20013 1 20012-000001 20012-20013 2 20012-000001 20012-20013 3 20012-000001 20012-20013 4 20012-000001 20012-20013 5
sqlSTR = "SELECT tblStudent.StudentID AS '??? ??????' , (tblStudent.FirstName + ' ' + tblStudent.MiddleName + ' ' + tblStudent.GrandFatherName + ' ' + tblStudent.LastName) as '?????' ," & _
"tblStudent.Gender as '?????', tblStudent.Citizenship as '???????', tblStudent.Type as '??? ?????'," & _
"tblDepartment.DepartmentTitle as '?????', tblEnrolment.SchoolYear as '????? ????????',tblYearLevel.YearLevelTitle as '????? ???????', " & _
"'????'= CASE WHEN Len(tblGraduate.StudentID)<>12 THEN '???' ELSE ''End , " & _
"'???? ???'= CASE WHEN Len(tblDropped.StudentID)<>12 THEN '???' ELSE ''End , " & _
"'??????'= CASE WHEN tblStudent.Transferee ='True' THEN '???' ELSE ''End" & _
" FROM tblDropped RIGHT JOIN " & _
"(tblGraduate RIGHT JOIN " & _
"(tblDepartment RIGHT JOIN " & _
"(tblYearLevel RIGHT JOIN " & _
"(tblSection RIGHT JOIN " & _
"(tblStudent LEFT JOIN tblEnrolment " & _
"ON tblStudent.StudentID = tblEnrolment.StudentID) " & _
"ON tblSection.SectionID = tblEnrolment.SectionOfferingID) " & _
"ON tblYearLevel.YearLevelID = tblEnrolment.YearLevelID) " & _
"ON tblDepartment.DepartmentID = tblSection.DepartmentID) " & _
"ON tblGraduate.StudentID = tblStudent.StudentID) " & _
"ON tblDropped.StudentID = tblStudent.StudentID" & _
" " & sFilter & _
" ORDER BY tblStudent.StudentID DESC , tblYearLevel.YearLevelTitle ASC"
母親...... O_O(抱歉,無法抗拒) – fresskoma 2012-07-28 20:44:13