0
OUT_RC = 37 ORA-01400: cannot insert NULL into ("PARTY"."SOURCE_SYSTEM_PARTY_CHARC"."PTY_CHARC_TY_VLU"): ORA-06512: at "PARTY.UP_MANAGE_SRC_SYS_PARTY_CHAR", line 131
我收到此錯誤信息,但線131是MERGE
聲明如何調試此SQL錯誤消息「無法插入NULL」?
MERGE INTO PARTY.SOURCE_SYSTEM_PARTY_CHARC SSPC
USING (SELECT l_sspc_chgs(index).PTY_CHARC_TY_ID AS PTY_CHARC_TY_ID,
l_sspc_chgs(index).SRC_SYS_PTY_ID AS SRC_SYS_PTY_ID, ...
她EIS更多的代碼(包圍上述MERGE
行:
OPEN SRC_SYS_PTY_CHARC_STG_CUR;
LOOP
FETCH SRC_SYS_PTY_CHARC_STG_CUR
BULK COLLECT INTO l_sspc_chgs LIMIT blklimit;
FOR indx IN 1 .. l_sspc_chgs.COUNT
LOOP
IF (l_sspc_chgs(indx).DLTD_IND = 'N')
THEN
MERGE INTO PARTY.SOURCE_SYSTEM_PARTY_CHARC SSPC
USING (SELECT l_sspc_chgs(indx).PTY_CHARC_TY_ID AS PTY_CHARC_TY_ID,
l_sspc_chgs(indx).SRC_SYS_PTY_ID AS SRC_SYS_PTY_ID,
l_sspc_chgs(indx).PTY_CHARC_TY_VLU AS PTY_CHARC_TY_VLU,
SYSTIMESTAMP AS CREATE_TS,
USER AS CREATE_USER_ID,
SYSTIMESTAMP AS UPDATE_TS,
USER AS UPDATE_USER_ID
FROM DUAL) SRC
ON (SSPC.PTY_CHARC_TY_ID = SRC.PTY_CHARC_TY_ID
AND SSPC.SRC_SYS_PTY_ID = SRC.SRC_SYS_PTY_ID)
WHEN MATCHED THEN
UPDATE SET PTY_CHARC_TY_VLU = SRC.PTY_CHARC_TY_VLU
,UPDATE_TS = SRC.UPDATE_TS
,UPDATE_USER_ID = SRC.UPDATE_USER_ID
WHEN NOT MATCHED THEN
INSERT (SRC_SYS_PTY_CHARC_ID, PTY_CHARC_TY_ID, SRC_SYS_PTY_ID,
PTY_CHARC_TY_VLU, CREATE_TS, CREATE_USER_ID,
UPDATE_TS, UPDATE_USER_ID)
VALUES (
SOURCE_SYSTEM_PARTY_CHARC_SEQ.NEXTVAL,
...
l_sspc_chgs
用於批量收集(自頂部代碼):
TYPE sspc_chgs IS TABLE OF SRC_SYS_PTY_CHARC_STG_CUR%ROWTYPE
INDEX BY PLS_INTEGER;
l_sspc_chgs sspc_chgs;
顯示你有更多的SQL代碼,什麼是'l_sspc_chgs(指數).PTY_CHARC_TY_ID'等? – zaratustra 2014-09-03 14:17:15
這是一個SELECT試圖插入NULL我認爲的MERGE。檢查你的SELECT。 – 2014-09-03 14:17:33
@zaratustra - 好的,添加它 – Coffee 2014-09-03 14:18:38