2013-07-03 58 views
1

我有一個類的UserData序列化對象,StreamCorruptedException而反序列化對象

import java.io.*; 

public final class UserData implements Serializable 
{ 
    private String name,username,password; 
    private boolean male; 
    private int age; 

    public void setName(String name) { this.name = new String(name); } 
    public void setUsername(String username) {this.username = new String(username); } 
    public void setPassword(String password) {this.password = new String(password); } 
    public void setAge(int age) { this.age = age; } 
    public void setGender(boolean gender) { this.male = gender; } 

    public String getName() { return new String(this.name); } 
    public String getUsername() { return new String(this.username); } 
    public String getPassword() { return new String(this.password); } 
    public int getAge() { return this.age; } 
    public boolean getGender() { return male; } 

    public static void writeUserDataToFile(UserData data,String fileName) 
    { 
     try 
     { 
      if(data == null) 
      { 
       return; 
      } 
      ObjectOutputStream objOutput = new ObjectOutputStream(new FileOutputStream(new File(fileName),true)); 
      objOutput.writeObject(data); 
      objOutput.flush(); 
      objOutput.close(); 
     } 
     catch(FileNotFoundException ex) 
     { 
      System.out.println("Error : Cannot Save Data , The given filename \""+fileName+"\" is not valid."); 
      return; 
     } 
     catch(NotSerializableException ex) 
     { 
      System.out.println("Error : It has been found that some data is not Serializable!"); 
      return; 
     } 
     catch(IOException ex) 
     { 
      System.out.println("Error : IOException has been encountered,"); 
      return; 
     } 
     catch(SecurityException S) 
     { 
      System.out.println("Error : Security Exception has been Encountered."); 
      return; 
     } 
     catch(Exception e) 
     { 
      System.out.println("Error : Unknown Exception thrown!"); 
      return; 
     } 
     System.out.println("Sucess : Data written to \""+fileName+"\"."); 
    } 
    public static UserData checkCredentials(String fileName,String userName,String passWord) 
    { 
     try 
     { 
      ObjectInputStream objInput = new ObjectInputStream(new FileInputStream(new File(fileName))); 
      UserData data; 
      while((data = (UserData)objInput.readObject())!=null) 
      { 
       if(userName.equals(data.getUsername()) && passWord.equals(data.getPassword())) 
        return data; 
      } 
      objInput.close(); 
     } 
     catch(Exception ex) 
     { 
      System.out.println("Error : Unknown Exception Caught while deserializing object."); 
      ex.printStackTrace(); 
     } 
     return null; 
    } 
} 

爲了測試這個類,我寫了另一個類,

public class TestUserData 
{ 
    public static void main(String args[]) 
    { 
     UserData data = new UserData(); 
     System.out.println("Serializing objects .... "); 
     for(int i=0;i<5;i++) 
     { 
      data.setName("John"); 
      data.setAge(10+i); 
      data.setGender((i%2==0)?true:false); 
      data.setUsername("John"+i); 
      data.setPassword(i+"John"); 
      UserData.writeUserDataToFile(data,"testSerial.dat"); 
     } 
     System.out.println("de-Serializing objects .... "); 
     for(int i=0;i<5;i++) 
     { 
      data = UserData.checkCredentials("testSerial.dat","John"+i,i+"John"); 
      if(data!=null) 
      { 
       System.out.println("Name : "+data.getName()); 
       System.out.println("Age : "+data.getAge()); 
       System.out.println("Gender : "+(data.getGender() ? "Male" : "Female")); 
      } 
      else 
      { 
       System.out.println("Data for Object "+i+" not de-serialized."); 
      } 
     } 
    } 
} 

輸出我得到

Serializing objects .... 
Sucess : Data written to "testSerial.dat". 
Sucess : Data written to "testSerial.dat". 
Sucess : Data written to "testSerial.dat". 
Sucess : Data written to "testSerial.dat". 
Sucess : Data written to "testSerial.dat". 
de-Serializing objects .... 
Name : John 
Age : 10 
Gender : Male 
Error : Unknown Exception Caught while deserializing object. 
java.io.StreamCorruptedException: invalid type code: AC 
    at java.io.ObjectInputStream.readObject0(ObjectInputStream.java:1374) 
    at java.io.ObjectInputStream.readObject(ObjectInputStream.java:369) 
    at UserData.checkCredentials(UserData.java:67) 
    at TestUserData.main(TestUserData.java:19) 
Data for Object 1 not de-serialized. 
Error : Unknown Exception Caught while deserializing object. 
java.io.StreamCorruptedException: invalid type code: AC 
    at java.io.ObjectInputStream.readObject0(ObjectInputStream.java:1374) 
    at java.io.ObjectInputStream.readObject(ObjectInputStream.java:369) 
    at UserData.checkCredentials(UserData.java:67) 
    at TestUserData.main(TestUserData.java:19) 
Data for Object 2 not de-serialized. 
Error : Unknown Exception Caught while deserializing object. 
java.io.StreamCorruptedException: invalid type code: AC 
    at java.io.ObjectInputStream.readObject0(ObjectInputStream.java:1374) 
    at java.io.ObjectInputStream.readObject(ObjectInputStream.java:369) 
    at UserData.checkCredentials(UserData.java:67) 
    at TestUserData.main(TestUserData.java:19) 
Data for Object 3 not de-serialized. 
Error : Unknown Exception Caught while deserializing object. 
java.io.StreamCorruptedException: invalid type code: AC 
    at java.io.ObjectInputStream.readObject0(ObjectInputStream.java:1374) 
    at java.io.ObjectInputStream.readObject(ObjectInputStream.java:369) 
    at UserData.checkCredentials(UserData.java:67) 
    at TestUserData.main(TestUserData.java:19) 
Data for Object 4 not de-serialized. 

在TestUserData類中,我是seri對5個UserData對象進行校準,序列化發生的很好,但在反序列化部分,它不能反序列化第一個對象。

我該如何改變才能使程序反序列化所有對象?

回答

1

你不能像這樣追加到序列化文件。但是也有一些寫頭,所以在你的文件,你將有<header><data><header><data><header><data>...

的文件需要形式<header><data><data><data><data>

的所以當你的閱讀方法是正確的,你的儲蓄方法其實是錯誤的。您需要同時寫入所有進入同一文件的對象。

+0

但在我的情況下,我無法同時序列化所有對象,因爲最初的目的是在用戶在任何時候創建帳戶的應用程序中使用它(我的意思不是在同一時間) 任何除了序列化以外的其他選擇? – cyberpirate92

+0

通過序列化,您需要將對象讀入內存,進行必要的更改(如添加用戶),然後將它們全部寫回到文件中。另一個簡單的方法是使用一個文本文件,例如CSV格式,每個用戶都有一行。更健壯的解決方案是使用數據庫(例如Java DB)。 – Kayaman

+0

所以我必須反序列化所有對象,然後再次序列化它們在同一時間?但是這不會增加開銷嗎? – cyberpirate92