什麼是最efficent方式，通過查詢

Question

生成以下的has_many我有以下型號：

帳戶

class Account < ActiveRecord::Base 
    has_many :members 
    has_many :users, through: :members 
end 

會員

class Member < ActiveRecord::Base 
    belongs_to :account 
    belongs_to :user 
end 

用戶

class User < ActiveRecord::Base 
    has_many :accounts, through: :members 
end 

查詢： 給定一個User.id，發現該帳戶。目前，我這樣做：

> u = User.take 
User Load (1.5ms) SELECT "users".* FROM "users" LIMIT 1 
> id = Member.where(user_id: u.id).pluck(:account_id) 
(0.8ms) SELECT "members"."account_id" FROM "members" WHERE "members"."user_id" = 1 
> a = Account.find(id) 
Account Load (8.9ms) SELECT "accounts".* FROM "accounts" WHERE "accounts"."id" = $1 LIMIT 1 [["id", 1]] 

知道是否有一個更好更快的方式找到客戶，給用戶？

Answer 1

我不知道你的模型的細節，但是基於錯誤，它看起來像你需要在User模型members協會：

class User < ActiveRecord::Base 
    has_many :members 
    has_many :accounts, through: :members 
end 

Answer 2

爲什麼不

u = User.take 
a = u.accounts.find(id)