創建一個等於加入查詢結果的新變量

Question

我在頁面上運行下面的查詢，其中有一個名爲$u的會話變量。我想從下面的查詢中創建一個變量$points等於totalScore2，其中l.username等於$u。字段l.username將僅等於$u一次。

我該怎麼做？

由於提前，

約翰

$sqlStr5 = "SELECT 
    l.loginid, 
    l.username, 
    l.created, 
    DATEDIFF(NOW(), l.created) + COALESCE(s.total, 0) * 5 + COALESCE(scs.total, 0) * 10 - COALESCE(nscs.total, 0) * 10 + COALESCE(c.total, 0) AS totalScore2 
FROM login l  
LEFT JOIN (
    SELECT loginid, COUNT(1) AS total 
    FROM submission 
    GROUP BY loginid 
) s ON l.loginid = s.loginid 
LEFT JOIN (
    SELECT loginid, COUNT(1) AS total 
    FROM comment 
    GROUP BY loginid 
) c ON l.loginid = c.loginid 

LEFT JOIN (
    SELECT S2.loginid, COUNT(1) AS total 
    FROM submission S2 
    INNER JOIN comment C2 
    ON C2.submissionid = S2.submissionid 
    GROUP BY S2.loginid 
) scs ON scs.loginid = l.loginid 


LEFT JOIN (
    SELECT S2.loginid, COUNT(1) AS total 
    FROM submission S2 
    INNER JOIN comment C2 
    ON C2.submissionid = S2.submissionid 
    AND C2.loginid = S2.loginid 
    GROUP BY S2.loginid 
) nscs ON nscs.loginid = l.loginid 



GROUP BY l.loginid 
ORDER BY totalScore2 DESC "; 

Answer 1

這工作：

$resultp = mysql_query($sqlStr5); 
$count = 1; 


while($rowp = mysql_fetch_array($resultp)) 
{ 
    if($u == $rowp['username']) 
    { 

$points = $rowp['totalScore2']; 

    } 
    $count++; 
}