在PostgreSQL中滾動12個月的總和

我需要能夠使用SQL（PostgreSQL）創建一個拖尾的十二個月報表 - 基本上是一個窗口/滾動12個月的總和，將當前月份的總計+每個月的前11個月總和。在PostgreSQL中滾動12個月的總和

我有這個表：

CREATE TABLE order_test(
order_id text, 
sale_date date, 
delivery_date date, 
customer_id text, 
vendor_id text, 
order_total float);

使用這些值：

insert into order_test 
values ('1', '2016-06-01', '2016-06-10', '2', '3', 200.10), 
    ('2', '2016-06-02', '2016-06-11', '2', '4', 150.50), 
    ('3', '2016-07-02', '2016-07-11', '5', '4', 100.50), 
    ('4', '2016-07-02', '2016-07-11', '1', '4', 150.50), 
    ('5', '2016-07-02', '2016-07-11', '1', '4', 150.50), 
    ('6', '2016-08-02', '2016-08-11', '6', '4', 300.50), 
    ('7', '2016-08-02', '2016-08-11', '6', '4', 150.50), 
    ('8', '2016-09-02', '2016-09-11', '1', '4', 150.50), 
    ('9', '2016-10-02', '2016-10-11', '1', '4', 150.50), 
    ('10', '2016-11-02', '2016-11-11', '1', '4', 150.50), 
    ('11', '2016-12-02', '2016-12-11', '6', '4', 150.50), 
    ('12', '2017-01-02', '2017-01-11', '7', '4', 150.50), 
    ('13', '2017-01-02', '2017-01-11', '1', '4', 150.50), 
    ('14', '2017-01-02', '2017-01-11', '1', '4', 100.50), 
    ('15', '2017-02-02', '2017-02-11', '1', '4', 150.50), 
    ('16', '2017-02-02', '2017-02-11', '1', '4', 150.50), 
    ('17', '2017-03-02', '2017-03-11', '2', '4', 150.50), 
    ('18', '2017-03-02', '2017-03-11', '2', '4', 150.50), 
    ('19', '2017-04-02', '2017-04-11', '6', '4', 120.50), 
    ('20', '2017-05-02', '2017-05-11', '1', '4', 150.50), 
    ('21', '2017-06-02', '2017-06-11', '2', '4', 150.50), 
    ('22', '2017-06-02', '2017-06-11', '1', '4', 130.50), 
    ('23', '2017-07-02', '2017-07-11', '1', '4', 150.50), 
    ('24', '2017-07-02', '2017-07-11', '5', '4', 200.50), 
    ('25', '2017-08-02', '2017-08-11', '1', '4', 150.50), 
    ('26', '2017-09-02', '2017-09-11', '2', '4', 100.50), 
    ('27', '2017-09-02', '2017-10-11', '1', '4', 150.50);

這些都是個人銷售。對於每個月，我需要前11個月+當月的總額（銷售月）。

我已經嘗試了窗口的計算是這樣的：

select date_trunc('month', sale_date) as sale_month, 
     sum(order_total) over w as total_sales 
from order_test 
where (delivery_date < current_date) and 
     (sale_date >= (date_trunc('month', current_date) - interval '1 year')) 
window w as (Partition by date_trunc('month', sale_date) 
      order by sale_date 
      rows between current row and 11 following)

，但它給我這個：

 sale_month total_sales 
1 01.09.2016 00:00:00 150,5 
2 01.10.2016 00:00:00 150,5 
3 01.11.2016 00:00:00 150,5 
4 01.12.2016 00:00:00 150,5 
5 01.01.2017 00:00:00 401,5 
6 01.01.2017 00:00:00 251 
7 01.01.2017 00:00:00 100,5 
8 01.02.2017 00:00:00 301 
9 01.02.2017 00:00:00 150,5 
10 01.03.2017 00:00:00 301 
11 01.03.2017 00:00:00 150,5 
12 01.04.2017 00:00:00 120,5 
13 01.05.2017 00:00:00 150,5 
14 01.06.2017 00:00:00 281 
15 01.06.2017 00:00:00 130,5 
16 01.07.2017 00:00:00 351 
17 01.07.2017 00:00:00 200,5 
18 01.08.2017 00:00:00 150,5 
19 01.09.2017 00:00:00 100,5

那裏應該只有每月一排。

來源

2017-09-20 Jared Stufft

組？ – Adriani6

你有沒有數據丟失的月份？ –

@VamsiPrabhala不，每個月至少應該有一條記錄。 –

在內部查詢派生表，您需要截斷使用date_trunc和group by結果列得到Month_total銷售，然後在外部查詢Sale_Date列month精度，使用累積窗口sum功能上month_total銷售數據排序通過Sale_Month得到您想要的結果如下。

SELECT sale_Month 
    ,month_total 
    ,sum(month_total) OVER (
     ORDER BY sale_Month ASC rows BETWEEN 11 preceding 
       AND CURRENT row 
     ) AS Sum_Series 
FROM (
    SELECT date_trunc('month', Sale_Date) AS Sale_Month 
     ,sum(Order_Total) AS Month_Total 
    FROM order_test 
    GROUP BY 1 
    ORDER BY 1 
    ) t

請注意，AND CURRENT row是可選的，因爲累積的窗函數包括current排在默認情況下，這樣的查詢可以改寫如下。

SELECT sale_Month 
    ,month_total 
    ,sum(month_total) OVER (
     ORDER BY sale_Month ASC rows 11 preceding 
     ) AS Sum_Series 
FROM (
    SELECT date_trunc('month', Sale_Date) AS Sale_Month 
     ,sum(Order_Total) AS Month_Total 
    FROM order_test 
    GROUP BY 1 
    ORDER BY 1 
    ) t

Result:

sale_month   month_total sum_series 
---------------------------------------------- 
2016-06-01T00:00:00Z 350.6   350.6 
2016-07-01T00:00:00Z 401.5   752.1 
2016-08-01T00:00:00Z 451   1203.1 
2016-09-01T00:00:00Z 150.5   1353.6 
2016-10-01T00:00:00Z 150.5   1504.1 
2016-11-01T00:00:00Z 150.5   1654.6 
2016-12-01T00:00:00Z 150.5   1805.1 
2017-01-01T00:00:00Z 401.5   2206.6 
2017-02-01T00:00:00Z 301   2507.6 
2017-03-01T00:00:00Z 301   2808.6 
2017-04-01T00:00:00Z 120.5   2929.1 
2017-05-01T00:00:00Z 150.5   3079.6 
2017-06-01T00:00:00Z 281   3010 
2017-07-01T00:00:00Z 351   2959.5 
2017-08-01T00:00:00Z 150.5   2659 
2017-09-01T00:00:00Z 251   2759.5

您可以按月檢查演示here

來源

2017-09-20 14:58:30 zarruq

我能弄明白，我們的答案是一致的。謝謝！ –

如果我理解正確，您希望所有月份都有過去11個月的累計數據。但前11行不會有前11個條目來計算滾動總和。但是你提到所有月份應該有累計總數。所以我相信你正在尋找這樣的東西。

with x as (
select date_trunc('month', sale_date) as sale_month,sum(order_total) as monthly_order_total from order_test 
group by 1 order by 1 asc) 

select sale_month, monthly_order_total, 
sum(monthly_order_total) over (order by sale_month asc rows between 11 preceding and current row) 

from x

來源

2017-09-20 14:52:50

在PostgreSQL中滾動12個月的總和

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