IndentationError：意外的未加註

Question

不久前開始編碼，大約一個月左右。我目前編碼不和諧殭屍，一切工作正常，直到我嘗試添加新命令之後運行機器人時，此錯誤消息：

Traceback (most recent call last): 
    File "C:\Users\Jeriel\Desktop\JerryBot\run.py", line 162, in main 
    from musicbot import MusicBot 
    File "C:\Users\Jeriel\Desktop\JerryBot\musicbot\__init__.py", line 1, in <modu 
le> 
    from .bot import MusicBot 
    File "C:\Users\Jeriel\Desktop\JerryBot\music\bot.py", line 2094 
    if __name__ == "__main__": 
          ^
IndentationError: unexpected unindent 

它開始我加入這之後我檢查每一行之前，我無法找到一個單一的任何地方：

async def kick(message,*args): 
     """Kicks the specified user from the server""" 
     if len(message.mentions) < 1: 
      return False 

     if message.channel.is_private: 
      msg = await client.send_message(message.channel,'Users cannot be kicked/banned from private channels.') 
      asyncio.ensure_future(message_timeout(msg, 40)) 
      return 

     if not message.channel.permissions_for(message.server.get_member(client.user.id)).kick_members: 
      msg = await client.send_message(message.channel, message.author.mention + ', I do not have permission to kick users.') 
      asyncio.ensure_future(message_timeout(msg, 40)) 
      return 

     members = [] 

     if not message.channel.is_private and message.channel.permissions_for(message.author).kick_members: 
      for member in message.mentions: 
       if member != message.author: 
        try: 
         await client.kick(member) 
         members.append(member.name) 
        except: 
         pass 
       else: 
        msg = await client.send_message(message.channel, message.author.mention + ', You should not kick yourself from a channel, use the leave button instead.') 
        asyncio.ensure_future(message_timeout(msg, 40)) 
     else: 
      msg = await client.send_message(message.channel, message.author.mention + ', I do not have permission to kick users, or this is a private message channel.') 
      asyncio.ensure_future(message_timeout(msg, 40)) 

     msg = await client.send_message(message.channel,'Successfully kicked user(s): `{}`'.format('`, `'.join(members))) 
     asyncio.ensure_future(message_timeout(msg, 60)) 

    @register('ban','@<mention users>',owner=True) 

    async def ban(message,*args): 
     """Bans the specified user from the server""" 
     if len(message.mentions) < 1: 
      return False 

     if message.channel.is_private: 
      msg = await client.send_message(message.channel,'Users cannot be kicked/banned from private channels.') 
      asyncio.ensure_future(message_timeout(msg, 40)) 
      return 

     if not message.channel.permissions_for(message.server.get_member(client.user.id)).ban_members: 
      msg = await client.send_message(message.channel, message.author.mention + ', I do not have permission to ban users.') 
      asyncio.ensure_future(message_timeout(msg, 40)) 
      return 

     members = [] 

     if message.channel.permissions_for(message.author).ban_members: 
      for member in message.mentions: 
       if member != message.author: 
        try: 
         await client.ban(member) 
         members.append(member.name) 
        except: 
         pass 
       else: 
        msg = await client.send_message(message.channel, message.author.mention + ', You should not ban yourself from a channel, use the leave button instead.') 
        asyncio.ensure_future(message_timeout(msg, 40)) 
     else: 
      msg = await client.send_message(message.channel, message.author.mention + ', I do not have permission to ban users, or this is a private message channel.') 
      asyncio.ensure_future(message_timeout(msg, 40)) 

     msg = await client.send_message(message.channel,'Successfully banned user(s): `{}`'.format('`, `'.join(members))) 
     asyncio.ensure_future(message_timeout(msg, 30)) 

    @register('bans',alias='bannedusers') 
    @register('bannedusers') 


if __name__ == "__main__": 
    bot = JerryBot() 
    bot.run("---") 

Answer 1

你的問題在這裏：

@register('bans',alias='bannedusers') 
    @register('bannedusers') 


if __name__ == "__main__": 
    bot = JerryBot() 
    bot.run("---") 

裝飾語法要求下@線函數的定義，它必須有相同的縮進水平爲@。換句話說，你不能在那裏陳述if陳述。你需要一個函數定義。縮進只是它發現的第一個問題;如果您縮進您的if聲明，則會得到不同的錯誤。

我不能告訴你是否在這裏包含了@行錯誤，或者你忽略了一個你想放在那裏的函數定義。要麼寫入函數，要麼刪除@行，以適合您的目的。

Answer 2

是否有可能您混合製表符和空格？這是python初學者的常見錯誤。從技術上講，你可以使用但不能混合它們。我的解決方案（我使用vim作爲IDE）是在我的.vimrc中設置tab鍵實際上是4個空格。

您可以嘗試在vim中重新鍵入gg=G並在命令模式下按回車鍵。