選擇那些具有特定列:
In [11]: df[df['from_date'] == 19951227]
Out[11]:
instrument type from_date to_date
0 96000001 W/D & V/L 19951227 19960102
1 96000002 DEED TRUST 19951227 19960102
或合併幾個查詢(可以使用|
爲或)
In [12]: df[(19951227 <= df['from_date']) & (df['to_date'] <= 19960102)]
Out[12]:
instrument type from_date to_date
0 96000001 W/D & V/L 19951227 19960102
1 96000002 DEED TRUST 19951227 19960102
2 96000003 WARNTY DEED 19951228 19960102
3 96000004 DEED TRUST 19951228 19960102
4 96000005 W/D & V/L 19951228 19960102
值得注意的是,這些列不是日期時間/時間戳對象。 ..
要將這些列轉換爲時間戳,您可以使用:
In [21]: pd.to_datetime(df['from_date'].astype(str))
Out[21]:
0 1995-12-27 00:00:00
1 1995-12-27 00:00:00
2 1995-12-28 00:00:00
3 1995-12-28 00:00:00
4 1995-12-28 00:00:00
Name: from_date, dtype: datetime64[ns]
In [22]: df['from_date'] = pd.to_datetime(df['from_date'].astype(str))
In [23]: pd.to_datetime(df['from_date'].astype(str)) # do same for to_date
,並通過最新的字符串表示查詢:
In [24]: df['1995-12-27' == df['from_date']]
Out[24]:
instrument type from_date to_date
0 96000001 W/D & V/L 1995-12-27 00:00:00 19960102
1 96000002 DEED TRUST 1995-12-27 00:00:00 19960102
安迪·海登,西部最快的槍。 –
http://en.wikipedia.org/wiki/The_Typing_of_the_Dead –
如何做類似於df ['1995-12-27'> = df ['from_date']&df ['1997-12-27'<= df ['從日期'] ] ? – Aidis