我是多線程新手,任何答案都將不勝感激。我正在運行一個使用3個線程的教程的例子;兩個由用戶創建,另一個用於主體本身。下面的代碼:多線程C
#include <stdio.h>
#include <pthread.h>
#include <string.h>
#include <stdlib.h>
#define NUM_EMPLOYEES 2
/* global mutex for our program. assignment initializes it */
pthread_mutex_t a_mutex = PTHREAD_MUTEX_INITIALIZER;
struct employee {
int number;
int id;
char first_name[20];
char last_name[30];
char department[30];
int room_number;
};
/* global variable - our employees array, with 2 employees */
struct employee employees[] = {
{1, 12345678, "danny", "cohen", "Accounting", 101},
{2, 87654321, "moshe", "levy", "Programmers", 202}
};
/* global variable - employee of the day */
struct employee employee_of_the_day;
void copy_employee(struct employee *from, struct employee *to) {
int rc; /* contain mutex lock/unlock results */
/*lock the mutex, to assure exclusive access to 'a' and 'b' */
rc = pthread_mutex_lock(&a_mutex);
to->number = from->number;
to->id = from->id;
strcpy(to->first_name, from->first_name);
strcpy(to->last_name, from->last_name);
strcpy(to->department, from->department);
to->room_number = from->room_number;
/* unlock mutex */
rc = pthread_mutex_unlock(&a_mutex);
}
/* function to be executed by the variable setting threads thread */
void *do_loop(void *data) {
int my_num = *((int*)data);
while(1) {
/* set employee of the day to be the one with number 'my_num' */
copy_employee(&employees[my_num-1], &employee_of_the_day);
}
}
/* program's execution begins in main */
int main(int argc, char *argv[]) {
int i;
int thr_id1;
int thr_id2;
pthread_t p_thread1;
pthread_t p_thread2;
int num1 = 1;
int num2 = 2;
struct employee eotd;
struct employee *worker;
/* initialize employee of the day to first 1 */
copy_employee(&employees[0], &employee_of_the_day);
/* create a new thread that will execute 'do_loop()' with '1' */
thr_id1 = pthread_create(&p_thread1, NULL, do_loop, (void*)&num1);
/* create a new thread that will execute 'do_loop()' with '2' */
thr_id2 = pthread_create(&p_thread2, NULL, do_loop, (void*)&num2);
/* run a loop that verifies integrity of 'employee of the day' many */
/* many times.... */
for (i = 0; i < 600000; i++) {
/* save contents of 'employee of the day' to local 'worker' */
copy_employee(&employee_of_the_day, &eotd);
worker = &employees[eotd.number-1];
/* compare employees */
if (eotd.id != worker->id) {
printf("mismatching 'id', %d != %d (loop '%d')\n",
eotd.id, worker->id, i);
exit(0);
}
if (strcmp(eotd.first_name, worker->first_name) != 0) {
printf("mismatching 'first_name' , %s != %s (loop '%d')\n",
eotd.first_name, worker->first_name, i);
exit(0);
}
if (strcmp(eotd.last_name, worker->last_name) != 0) {
printf("mismatching 'last_name' , %s != %s (loop '%d')\n",
eotd.last_name, worker->last_name, i);
exit(0);
}
if (strcmp(eotd.department, worker->department) != 0) {
printf("mismatching 'department' , %s != %s (loop '%d')\n",
eotd.department, worker->department, i);
exit(0);
}
if (eotd.room_number != worker->room_number) {
printf("mismatching 'room_number' , %d != %d (loop '%d')\n",
eotd.room_number, worker->room_number, i);
exit(0);
}
}
printf("Glory, employees contents was always consistent\n");
return 0;
}
我基本上要確認的是,在for循環爲主,下面的語句
copy_employee(&employee_of_the_day, &eotd);
可以由任何3個線程的執行;我對嗎? 事實上,隨後的比較顯然不是原子提出了一些混淆。對此的任何澄清/更正將大有幫助。
順便說一句,任何有關C多線程教程的良好建議?
非常感謝!
太好了。所以這意味着當在main中for循環中調用copy_employee()時,兩個工作線程中的任何一個都可以執行該函數?謝謝! – Iceman 2012-04-12 15:19:28
所有這三個線程都會在某個時間調用'copy_employee()',但使用不同的參數和代碼中的不同位置。互斥鎖確保只有一個線程同時複製代碼。 – Mario 2012-04-12 15:21:20
所以可以肯定的是,每次在for循環中,其主線程運行copy_employee(),對吧?代碼作者多次迭代的事實引起了混淆。 – Iceman 2012-04-12 15:25:36