根據列的相似性檢查所有其他列中的更改（續）

Question

select sum(case when NumFirstNames <> 1 then 1 else 0 end) as DifferentFirstNames, 
    sum(case when NumLastNames <> 1 then 1 else 0 end) as DifferentLastNames, 
    sum(case when NumSSN <> 1 then 1 else 0 end) as DifferentSSN, 
    sum(case when NumPhone <> 1 then 1 else 0 end) as DifferentPhone  
from (select EncounterId, count(*) as Num, 
count(distinct FirstName) as NumFirstNames, 
count(distinct LastName) as NumLastNames, 
count(distinct SSN) as NumSSN, 
count(distinct Phone) as NumPhone 
from table t 
group by EncounterId) e; 

我需要上面的查詢來對錶中另一列進行分組，名爲FacilityCode，以及顯示重複EncounterIDs的次數和列沒有缺陷。

另外，除了計數（即第一個查詢的結果背後的數據）之外，是否可以使用類似構建的查詢來拉取「缺陷」結果？

見鏈接前面的問題： Check for changes in all other columns based on similarities one column

Answer 1

是。只要把該列中的子查詢和聚集在外部查詢：

select FacilityCode, 
     sum(case when NumFirstNames <> 1 then 1 else 0 end) as DifferentFirstNames, 
     sum(case when NumLastNames <> 1 then 1 else 0 end) as DifferentLastNames, 
     sum(case when NumSSN <> 1 then 1 else 0 end) as DifferentSSN, 
     sum(case when NumPhone <> 1 then 1 else 0 end) as DifferentPhone  
from (select EncounterId, FacilityCode, count(*) as Num, 
      count(distinct FirstName) as NumFirstNames, 
      count(distinct LastName) as NumLastNames, 
      count(distinct SSN) as NumSSN, 
      count(distinct Phone) as NumPhone 
     from table t 
     group by EncounterId, FacilityCode 
    ) e 
group by FacilityCode; 

我不知道你所說的「拉缺陷導致」的意思。但子查詢（可能帶有合適的having子句）將獲得每個EncounterId的信息。