得到一天兩次之間的時間

Question

我已經試過用NSDate但沒有運氣。 我想要例如14:10和18:30之間的差異。

小時和分鐘。

我希望你能幫助我不應該是複雜的:)

Answer 1

的NSDate的類有做的伎倆的方法timeIntervalSinceDate。

NSTimeInterval secondsBetween = [firstDate timeIntervalSinceDate:secondDate]; 

NSTimeInterval是一個雙精度值，表示兩次之間的秒數。

Answer 2

這裏是我快速的解決方案：

NSDateFormatter *df = [[[NSDateFormatter alloc] init] autorelease]; 
[df setDateFormat:@"HH:mm"]; 
NSDate *date1 = [df dateFromString:@"14:10"]; 
NSDate *date2 = [df dateFromString:@"18:09"]; 
NSTimeInterval interval = [date2 timeIntervalSinceDate:date1]; 
int hours = (int)interval/3600;    // integer division to get the hours part 
int minutes = (interval - (hours*3600))/60; // interval minus hours part (in seconds) divided by 60 yields minutes 
NSString *timeDiff = [NSString stringWithFormat:@"%d:%02d", hours, minutes]; 

Answer 3

有沒有必要用手工計算這個，看看NSCalendar。如果你想獲得的小時和分鐘兩個日期之間，使用這樣的：

NSCalendar *gregorianCalendar = [[NSCalendar alloc] initWithCalendarIdentifier:NSGregorianCalendar]; 
NSUInteger unitFlags = NSHourCalendarUnit | NSMinuteCalendarUnit; 
NSDateComponents *components = [gregorianCalendar components:unitFlags 
                fromDate:firstDate 
                 toDate:otherDate 
                options:0]; 
[gregorianCalendar release]; 

您現在有小時和分鐘爲NSDateComponents並且可以訪問它們作爲NSIntegers像[components hour]和[components minute]。這也將工作幾天，閏年和其他有趣的東西幾個小時。

Answer 4

NSString *duration = [self calculateDuration:oldTime secondDate:currentTime]; 

- (NSString *)calculateDuration:(NSDate *)oldTime secondDate:(NSDate *)currentTime 
{ 
    NSDate *date1 = oldTime; 
    NSDate *date2 = currentTime; 

    NSTimeInterval secondsBetween = [date2 timeIntervalSinceDate:date1]; 

    int hh = secondsBetween/(60*60); 
    double rem = fmod(secondsBetween, (60*60)); 
    int mm = rem/60; 
    rem = fmod(rem, 60); 
    int ss = rem; 

    NSString *str = [NSString stringWithFormat:@"%02d:%02d:%02d",hh,mm,ss]; 

    return str; 
}