在兩個球員,PostgreSQL based game最頻繁調用語句是SELECT查詢返回的遊戲列表,用戶正在玩其中:如何使用多個CASE語句優化SELECT查詢?
(請原諒在截圖非拉丁字母)
CREATE OR REPLACE FUNCTION words_get_games(in_uid integer)
RETURNS TABLE (
out_gid integer,
out_created integer,
out_finished integer,
out_letters varchar[15][15],
out_values integer[15][15],
out_bid integer,
out_last_tiles jsonb,
out_last_score integer,
out_player1 integer,
out_player2 integer,
out_played1 integer,
out_played2 integer,
out_hand1 text,
out_hand2 text,
out_score1 integer,
out_score2 integer,
out_female1 integer,
out_female2 integer,
out_given1 varchar,
out_given2 varchar,
out_photo1 varchar,
out_photo2 varchar,
out_place1 varchar,
out_place2 varchar
) AS
$func$
SELECT
g.gid,
EXTRACT(EPOCH FROM g.created)::int,
EXTRACT(EPOCH FROM g.finished)::int,
g.letters,
g.values,
g.bid,
m.tiles,
m.score,
/* HOW TO OPTIMIZE THE FOLLOWING CASE STATEMENTS? */
CASE WHEN g.player1 = in_uid THEN g.player1 ELSE g.player2 END,
CASE WHEN g.player1 = in_uid THEN g.player2 ELSE g.player1 END,
CASE WHEN g.player1 = in_uid THEN g.score1 ELSE g.score2 END,
CASE WHEN g.player1 = in_uid THEN g.score2 ELSE g.score1 END,
CASE WHEN g.player1 = in_uid THEN s1.female ELSE s2.female END,
CASE WHEN g.player1 = in_uid THEN s2.female ELSE s1.female END,
CASE WHEN g.player1 = in_uid THEN s1.given ELSE s2.given END,
CASE WHEN g.player1 = in_uid THEN s2.given ELSE s1.given END,
CASE WHEN g.player1 = in_uid THEN s1.photo ELSE s2.photo END,
CASE WHEN g.player1 = in_uid THEN s2.photo ELSE s1.photo END,
CASE WHEN g.player1 = in_uid THEN s1.place ELSE s2.place END,
CASE WHEN g.player1 = in_uid THEN s2.place ELSE s1.place END,
EXTRACT(EPOCH FROM CASE WHEN g.player1 = in_uid THEN g.played1 ELSE g.played2 END)::int,
EXTRACT(EPOCH FROM CASE WHEN g.player1 = in_uid THEN g.played2 ELSE g.played1 END)::int,
ARRAY_TO_STRING(CASE WHEN g.player1 = in_uid THEN g.hand1 ELSE g.hand2 END, ''),
REGEXP_REPLACE(ARRAY_TO_STRING(CASE WHEN g.player1 = in_uid THEN g.hand2 ELSE g.hand1 END, ''), '.', '?', 'g'),
FROM words_games g
LEFT JOIN words_moves m ON m.gid = g.gid
-- find move record with the most recent timestamp
AND NOT EXISTS (SELECT 1
FROM words_moves m2
WHERE m2.gid = m.gid
AND m2.played > m.played)
LEFT JOIN words_social s1 ON s1.uid = g.player1
-- find social record with the most recent timestamp
AND NOT EXISTS (SELECT 1
FROM words_social s
WHERE s1.uid = s.uid
AND s.stamp > s1.stamp)
LEFT JOIN words_social s2 ON s2.uid = g.player2
-- find social record with the most recent timestamp
AND NOT EXISTS (SELECT 1
FROM words_social s
WHERE s2.uid = s.uid
AND s.stamp > s2.stamp)
WHERE in_uid IN (g.player1, g.player2)
AND (g.finished IS NULL OR g.finished > CURRENT_TIMESTAMP - INTERVAL '1 day');
$func$ LANGUAGE sql;
正如你可以在自定義的SQL函數見上面,在努力總是返回用戶數據player1
,given1
,score1
我使用大量的CASE語句(以便獲取ç需要時olumns可以被交換):
CASE WHEN g.player1 = in_uid THEN g.score1 ELSE g.score2 END,
我的問題是:如果它能夠優化上述SELECT查詢(無需切換到較慢的PL/pgSQL的)?
UPDATE:
傑夫在the mailing list在接合時提供了一個很好的建議,已經在使用CASE:
SELECT
g.gid,
EXTRACT(EPOCH FROM g.created)::int,
EXTRACT(EPOCH FROM g.finished)::int,
g.letters,
g.values,
g.bid,
m.tiles,
m.score,
CASE WHEN g.player1 = in_uid THEN g.player1 ELSE g.player2 END,
CASE WHEN g.player1 = in_uid THEN g.player2 ELSE g.player1 END,
CASE WHEN g.player1 = in_uid THEN g.score1 ELSE g.score2 END,
CASE WHEN g.player1 = in_uid THEN g.score2 ELSE g.score1 END,
s1.female,
s2.female,
s1.given,
s2.given,
s1.photo,
s2.photo,
s1.place,
s2.place,
EXTRACT(EPOCH FROM CASE WHEN g.player1 = in_uid THEN g.played1 ELSE g.played2 END)::int,
EXTRACT(EPOCH FROM CASE WHEN g.player1 = in_uid THEN g.played2 ELSE g.played1 END)::int,
ARRAY_TO_STRING(CASE WHEN g.player1 = in_uid THEN g.hand1 ELSE g.hand2 END, ''),
REGEXP_REPLACE(ARRAY_TO_STRING(CASE WHEN g.player1 = in_uid THEN g.hand2 ELSE g.hand1 END, ''), '.', '?', 'g')
FROM words_games g
LEFT JOIN words_moves m ON m.gid = g.gid
-- find move record with the most recent timestamp
AND NOT EXISTS (SELECT 1
FROM words_moves m2
WHERE m2.gid = m.gid
AND m2.played > m.played)
LEFT JOIN words_social s1 ON s1.uid = in_uid
-- find social record with the most recent timestamp
AND NOT EXISTS (SELECT 1
FROM words_social s
WHERE s1.uid = s.uid
AND s.stamp > s1.stamp)
LEFT JOIN words_social s2 ON s2.uid = (CASE WHEN g.player1 = in_uid THEN g.player2 ELSE g.player1 END)
-- find social record with the most recent timestamp
AND NOT EXISTS (SELECT 1
FROM words_social s
WHERE s2.uid = s.uid
AND s.stamp > s2.stamp)
WHERE in_uid IN (g.player1, g.player2)
AND (g.finished IS NULL OR g.finished > CURRENT_TIMESTAMP - INTERVAL '1 day');
你怎麼知道它是次優的?在查詢已經檢索到所需數據(一個用於遊戲,另外兩個用於玩家)之後,只有兩組值可能(或可能不需要)在外部查詢中交換。 – joop
是的,我我不確定。實際上,我想優化兩件事:性能和可讀性。 –
我不擔心大小寫表達式,因爲它們在選擇列表中。 – jarlh