添加方法中的值

Question

我有一個包含8個選擇題的應用程序，每個問題的答案都存儲在2個單選按鈕中。第一個單選按鈕的值爲choice1Value，第二個單選按鈕的值爲choice2Value。將這些響應整理在陣列choice1ValueArray[]和choice2ValueArray[]中。但是，方法+getTotalRisk()僅採用最後一個問題的值。事實上，它應該從所有問題中取得所有的值（取決於選擇哪個單選按鈕）並將它們加在一起。

private int getTotalRisk() { 
     int totalRisk = choice1Value + choice2Value; 
     return totalRisk; 
    } 

    public void submitButtonClicked() { 

     if (infoIsValid()) { 
      for (int i = 1; i < choice1Array.length; i++) { 
       username = "Johnny"; 
       questionID = i; 

       if (choice1Array[i].isSelected()) { 
        answer = choice1Array[i].getText(); 
       } else if (choice2Array[i].isSelected()) { 
        answer = choice2Array[i].getText(); 
       } 

       QuizAnswer q = new QuizAnswer(username, questionID, answer); 

       q.createQuizAnswer(); 

       if (choice1Array[i].isSelected()) { 
        choice1Value = choice1ValueArray[i]; 
       } 
       else if (choice2Array[i].isSelected()) { 
        choice2Value = choice2ValueArray[i]; 
       } 
        System.out.println("Risk Value is " + getTotalRisk()); 

      } 
      System.out.println("Your total risk value is " + getTotalRisk()); 
     } 

    } 

這是我輸出的結果，當點擊提交按鈕時。您可以看到它顯示了每個問題的風險值，但最終在最後時，它會計算所有風險值，但仍顯示0（您的總風險值爲0）。

connection is jdbc:odbc:myHealthDatabase 
DB Query: INSERT INTO QUIZANSWER (Username, QuestionID, Answer) VALUES ('Johnny', '1', 'Above 45') 
Connection is closed 
Risk Value is 1 
connection is jdbc:odbc:myHealthDatabase 
DB Query: INSERT INTO QUIZANSWER (Username, QuestionID, Answer) VALUES ('Johnny', '2', 'Yes') 
Connection is closed 
Risk Value is 3 
connection is jdbc:odbc:myHealthDatabase 
DB Query: INSERT INTO QUIZANSWER (Username, QuestionID, Answer) VALUES ('Johnny', '3', 'Yes') 
Connection is closed 
Risk Value is 2 
connection is jdbc:odbc:myHealthDatabase 
DB Query: INSERT INTO QUIZANSWER (Username, QuestionID, Answer) VALUES ('Johnny', '4', 'Yes') 
Connection is closed 
Risk Value is 3 
connection is jdbc:odbc:myHealthDatabase 
DB Query: INSERT INTO QUIZANSWER (Username, QuestionID, Answer) VALUES ('Johnny', '5', 'No') 
Connection is closed 
Risk Value is 2 
connection is jdbc:odbc:myHealthDatabase 
DB Query: INSERT INTO QUIZANSWER (Username, QuestionID, Answer) VALUES ('Johnny', '6', 'No') 
Connection is closed 
Risk Value is 2 
connection is jdbc:odbc:myHealthDatabase 
DB Query: INSERT INTO QUIZANSWER (Username, QuestionID, Answer) VALUES ('Johnny', '7', 'Yes') 
Connection is closed 
Risk Value is 1 
connection is jdbc:odbc:myHealthDatabase 
DB Query: INSERT INTO QUIZANSWER (Username, QuestionID, Answer) VALUES ('Johnny', '8', 'Yes') 
Connection is closed 
Risk Value is 0 
Your total risk value is 0 

Answer 1

陣列從零開始

for (int i = 1; i < rArray.length; i++) 

也許應該

for (int i = 0; i < rArray.length; i++) 

Answer 2

你沒有積累的結果（我覺得）你想，你繼續覆蓋answer，choice1Value和choice2Value每次通過for循環。這就是爲什麼你從最後一個問題獲得「價值」。

但很難在不知道更多的情況下更詳細地回答您的問題。正如卡薩布蘭卡在評論中所說，重要的信息在這裏不復存在。你想做什麼？什麼是answer以及它是如何使用的？什麼是你的g/v/r/fArray變量（你應該給他們更好的名字）？你能舉一個你的單選按鈕應該加起來的例子嗎？

您的評論後編輯：我覺得你需要像這樣加起來你的風險值：

public int getTotalRisk() { 
    if (!infoIsValid()) { 
    return 0; 
    } 
    int totalRisk = 0; 
    // assuming choice1Array.length == choice2Array.length...? 
    for (int i = 0; i < choice1Array.length; i++) { 
    if (choice1Array[i].isSelected()) { 
     answer = choice1Array[i].getText(); 
    } else if (choice2Array[i].isSelected()) { 
     answer = choice2Array[i].getText(); 
    } // is it possible for neither to be selected? 
    QuizAnswer quizAnswer = new QuizAnswer("Johnny", i, answer); 
    quizAnswer.createQuizAnswer(); // not sure what this line is meant to do 
    if (choice1Array[i].isSelected()) { 
     totalRisk += choice1ValueArray[i]; 
    } else if (choice2Array[i].isSelected()) { 
     totalRisk += choice2ValueArray[i]; 
    } // if one is always selected, make it if/else, not if/else if 
    } 
    return totalRisk; 
} 

我冒昧提出一些修改，隨意使用或忽略他們......重點是，爲了獲得總體風險，您需要每次通過for循環時加入一個變量（totalRisk），以便每個值i（和I已經使循環從0開始，即數組中的第一個位置，正如Peter的答案所示;如果有一個有效的循環從1開始的理由，例如a t在陣列中的第二個位置）。正如前面提到的，你正在做的是每次在循環中覆蓋「總」值，所以最後你得到了最後一個循環的值。

由於我不知道createQuizAnswer()方法是幹什麼的，所以我會讓你把它用在你的代碼中，但希望你能明白你做錯了什麼。作爲最終的一般性建議，您應該閱讀變量作用域，因爲我認爲您並不總是知道如何使用它們。