如何使用PHP動態過濾網站內容

我目前正在尋找解決方案來動態過濾網站內容。通過「動態」我的意思是我會計算第一頁上的整個單詞中不良詞的百分比，即shit,f**k等。如果百分比不超過30％，說網站是允許的。如何讓它搜索第一頁上的每個單詞，並將它們與不良單詞列表進行匹配，然後除以單詞的總數，以便我能夠得到該百分比？理由不是製作內容過濾器，而是僅僅阻止網站，即使頁面中的一個單詞與不良單詞列表匹配。我已經得到了這個，但它是靜態的。如何使用PHP動態過濾網站內容

$filename = "filters.txt"; 

$fp = @fopen($filename, 'r'); 

if ($fp) { 

$array = explode("\n", fread($fp, filesize($filename))); 

foreach($array as $key => $val){ 

list($before,$after) = split("~",$val); 

$input = preg_replace($before,$after,$input); 

} 
}

* filter.txt包含髒話

感謝名單Erisco列表！

試過這個，但它似乎並沒有工作。

function get_content($url) 
{ 
    $ch = curl_init(); 

    curl_setopt ($ch, CURLOPT_URL, $url); 
    curl_setopt ($ch, CURLOPT_HEADER, 0); 

    ob_start(); 

    curl_exec ($ch); 
    curl_close ($ch); 
    $string = ob_get_contents(); 

    ob_end_clean(); 

    return $string;  

} 


/* $toLoad is from Browse.php */ 

$sourceOfWebpage = get_content($toLoad); 
$textOfWebpage = strip_tags($sourceOfWebpage); 

/* array: Obtained by your filter.txt file */ 
// Open the filters file and filter all of the results. 

$filename = "filters.txt"; 
$badWords = @fopen($filename, 'r'); 

if ($badWords) { 
    $array = explode("\n", fread($fp, filesize($filename))); 

    foreach($array as $key => $val){ 
    list($before,$after) = split("~",$val); 
    $input = preg_replace($before,$after,$input); 
    } 
} 

/* float: Some decimal value */ 

$allowedBadWordsPercent = 0.30; 
$numberOfWords = str_word_count($textOfWebpage); 
$numberOfBadWords = 0; 
str_ireplace($badWords, '', $sourceOfWebpage, $numberOfBadWords); 

if ($numberOfBadWords != 0) { 
    $badWordsPercent = $numberOfWords/$numberOfBadWords; 
} else { 
    $badWordsPercent = 0; 
} 

if ($badWordsPercent > $allowedBadWordsPercent) { 
    echo 'This is a naughty webpage'; 
}

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2010-08-29 Khals Ismail

這是我想要做的粗略想法。你可以爭辯說，純粹用於計數的str_ireplace（）雖然是狡猾的。我不確定是否有更多的方向功能，而不會破壞正則表達式。

/* string: Obtained by CURL or similar */ 
$sourceOfWebpage; 

$textOfWebpage = strip_tags($sourceOfWebpage); 

/* array: Obtained by your filter.txt file */ 
$badWords; 

/* float: Some decimal value */ 
$allowedBadWordsPercent = 0.30; 

$numberOfWords = str_word_count($textOfWebpage); 
$numberOfBadWords = 0; 

str_ireplace($badWords, '', $sourceOfWebpage, $numberOfBadWords); 

if ($numberOfBadWords != 0) { 
    $badWordsPercent = $numberOfWords/$numberOfBadWords; 
} else { 
    $badWordsPercent = 0; 
} 

if ($badWordsPercent > $allowedBadWordsPercent) { 
    echo 'This is a naughty webpage'; 
}

來源

2010-08-29 16:06:46 erisco

如何使用PHP動態過濾網站內容

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