從扁平陣列從服務構建多維數組

Question

您好我正在接收平面陣列如下

[0] [] (@bf4f219) 
    [0] Object (@a55f1a9) 
     breadcrumb "{2}" 
     entity_name "parent 2" 
     id 2 
     level 1 
     parent_id 0 

    [1] Object (@a5be281) 
     breadcrumb "{2,4}" 
     entity_name "child for parent 2"  
     id 4 
     level 2 
     parent_id 2 

    [2] Object (@a5bea01) 
     breadcrumb "{2,4,5}" 
     entity_name "child for 4" 
     id 5 
     level 3 
     parent_id 4 

    [3] Object (@a5ed179) 
     breadcrumb "{2,4,5,7}" 
     entity_name "child for 5" 
     id 7 
     level 4 
     parent_id 5 

    [4] Object (@a5ed6d1) 
     breadcrumb "{2,6}" 
     entity_name "child 2 for parent 2" 
     id 6 
     level 2 
     parent_id 2 

    [5] Object (@a5edb09) 
     breadcrumb "{2,8}" 
     entity_name "another child for 2" 
     id 8 
     level 2 
     parent_id 2 

    [6] Object (@a5edda9) 
     breadcrumb "{2,9}" 
     entity_name "another child for 2" 
     id 9 
     level 2 
     parent_id 2 

我需要做的是根據id來構造多維數組和在每個對象PARENT_ID提供，請注意，如果這有助於每個項目也提供維度中的級別。

我有一個真正的大腦空白，不能找出這一個，請幫助，因爲我必須快速找到解決方案。

在此先感謝。

Answer 1

由於您可以在根級別擁有任意數量的parent_id，因此您最終可以擁有多棵樹。

嘗試了這一點，運氣好：

var trees:Array = buildTrees(FLAT); 

    private static const FLAT:Array = 
    [ 
     {breadcrumb: "{2}", entity_name: "parent 2", 
      id:   2, 
      level:  1, 
      parent_id: 0}, 

     {breadcrumb: "{2,4}", entity_name: "child for parent 2",  
      id:   4, 
      level:  2, 
      parent_id: 2}, 

     {breadcrumb: "{2,4,5}", entity_name: "child for 4", 
      id:   5, 
      level:  3, 
      parent_id: 4}, 

     {breadcrumb: "{2,4,5,7}", entity_name: "child for 5", 
      id:   7, 
      level:  4, 
      parent_id: 5}, 

     {breadcrumb: "{2,6}", entity_name: "child 2 for parent 2", 
      id:   6, 
      level:  2, 
      parent_id: 2}, 

     {breadcrumb: "{2,8}", entity_name: "another child for 2", 
      id:   8, 
      level:  2, 
      parent_id: 2}, 

     {breadcrumb: "{2,9}", entity_name: "another child for 2", 
      id:   9, 
      level:  2, 
      parent_id: 2} 
    ]; 

    private function buildTrees(flat:Array):Array 
    { 
     if (!flat.length) 
      return null; 

     flat.sortOn("parent_id", Array.NUMERIC); 

     var trees:Array = new Array(); 

     var i:uint; 

     for (i = 0; i < flat.length; i ++) 
     { 
      var node:Object = {parent_id: flat[i].parent_id, id: flat[i].id, level: flat[i].level, 
       breadcrumb: flat[i].breadcrumb, entity_name: flat[i].entity_name, nodes: new Array()}; 

      var root:Object = findRoot(flat[i].parent_id, trees); 

      if (root) { 
       root.nodes.push(node); 
      } 
      else 
       trees.push(node); 
     } 

     for (i = 0; i < trees.length; i ++) 
      sortTree(trees[i]); 

     return trees; 
    } 

    private function findRoot(parent_id:int, trees:Array):Object 
    { 
     for (var i:uint = 0; i < trees.length; i ++) 
     { 
      var node:Object = findNode(parent_id, trees[i]); 

      if (node) 
       return node; 
     } 

     return null; 
    } 

    private function findNode(parent_id:int, root:Object):Object 
    { 
     if (root.id == parent_id) 
      return root; 

     for (var i:uint = 0; i < root.nodes.length; i ++) 
     { 
      var node:Object = findNode(parent_id, root.nodes[i]); 

      if (node) 
       return node; 
     } 

     return null; 
    } 

    private function sortTree(root:Object):void 
    { 
     root.nodes.sortOn("level", Array.NUMERIC); 

     for (var i:uint = 0; i < root.nodes.length; i ++) 
      sortTree(root.nodes[i]); 
    }