0
我沒有很多運氣來搞清楚如何使用int和字符串進行查詢。我發現了兩個整數的例子,並且我找到了兩個字符串的例子。我嘗試了不同的組合,似乎沒有任何工作。以下是我嘗試過並沒有奏效的兩個例子。我究竟做錯了什麼。我自己使用了inpspection_id和item_name,它們都工作。使用int和字符串嘗試查詢
嘗試1:
public int getId(int inspection_id ,String item_name)throws Exception
{
Cursor c = db.query(DB_TABLE, new String[] {KEY_INSPECTION_ID, KEY_ITEM_NAME},
"inspection_id=" + inspection_id +"item_name='"+ item_name + "'", null, null, null, null);
int id=c.getColumnIndex(KEY_ROWID);
c.moveToFirst();
String result=c.getString(id);
int primId=Integer.parseInt(result);
c.close();
return primId;
}
嘗試2:
public int getId(int inspection_id ,String item_name)throws Exception
{
Cursor c = db.query(DB_TABLE, new String[] {KEY_INSPECTION_ID, KEY_ITEM_NAME},
"inspection_id=" + inspection_id +"AND KEY_ITEM_NAME = ?", new String[]{item_name}, null, null, null);
int id=c.getColumnIndex(KEY_ROWID);
c.moveToFirst();
String result=c.getString(id);
int primId=Integer.parseInt(result);
c.close();
return primId;
}
嘗試3:
public int getId(int inspection_id ,String item_name)throws Exception
{
String s_id= Integer.toString(inspection_id);
Cursor c = db.query(DB_TABLE, new String[] {KEY_INSPECTION_ID, KEY_ITEM_NAME},
"KEY_INSPECTION_ID = ? AND KEY_ITEM_NAME = ?",
new String[] { s_id, item_name }, null, null, null);
int id=c.getColumnIndex(KEY_ROWID);
c.moveToFirst();
String result=c.getString(id);
int primId=Integer.parseInt(result);
c.close();
return primId;
}
我試過了,它沒有工作 – Aaron 2012-04-15 20:46:14
感謝它竟然是別的東西,但當我改變它的評論工作 – Aaron 2012-04-15 21:57:20