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我想添加到一個存在的查詢2個新列。在第一個中,在當前行和下一個之間進行差異化,並在下一個之間對行之間的值進行計數。行之間的差異
我當前的查詢是:
SELECT *, SUM(MINUTE(rest_time)) AS Times
FROM routes as routes
LEFT JOIN sales
ON (routes.departure_poi_code = sales.client_code AND
routes.departure_date = sales.`date`)
WHERE (routes.departure_poi_code LIKE 'C0%' OR routes.departure_poi_code LIKE 'MP%')
AND routes.`car_no` = 'BH-07-EWR'
AND routes.departure_date = '2011-10-14'
GROUP BY routes.departure_address, reports.routes.departure_poi_code,
reports.routes.car_no, reports.routes.departure_date
ORDER BY routes.car_no
LIMIT 500000
和我的當前查詢的結果是一樣的東西:
Car_Numbr Str_time Cod_nr KM
BH-07-EWR 08:59:00 C00425 7000
BH-07-EWR 10:29:00 C00149 8500
BH-07-EWR 14:27:00 C01075 9200
BH-07-EWR 15:07:00 C00305 9800
BH-07-EWR 16:08:00 C02572 9900
當然,它包含多個列,但它是不相關的顯示在這裏所有的人。
故事是一輛汽車將從客戶端1到客戶端2的row2.km-row1.km等等。當然,汽車公里是它在船上的。 而且我想它是:
Car_Number Start_time Code_nr KM Total_km Diff_km
BH-07-EWR 08:59:00 C00425 7000 0 (km counter starting from 0) 0 (first row show have 0)
BH-07-EWR 10:29:00 C00149 8500 1500 (0+8500-7000) 1500 (8500-7000)
BH-07-EWR 14:27:00 C01075 9200 2200 (upper result+9200-8500) 700 (9200-8500)
BH-07-EWR 15:07:00 C00305 9800 2800 (upper result+9800-9200) 600 (9800-9200)
BH-07-EWR 16:08:00 C02572 9900 2900 (upper result+9900-9800) 100 (9900-9800)
我怎樣才能實現這個最簡單的方法?
檢查:http://stackoverflow.com/questions/5402938/mysql-find-difference-between-rows-of-the-the-the-table – Sterex 2012-01-30 07:07:00