如何decleare char * const的的argv []中迅速

Question

我想使字符的交流風格數組指針這樣的：

*const argv[] 

我想通了，我必須使用UnsafePointer<UnsafeMutablePointer<Int8>>

但我不不知道如何初始化它。

我該如何映射這種正常的陣列來UnsafePointer<UnsafeMutablePointer<Int8>>：

let argv = ["/usr/bin/printf", "BBB"] 

謝謝

Answer 1

最簡單的辦法是讓可可形成你的C字符串：

let args = ["/usr/bin/printf","BBB"] 
var cs = UnsafeMutablePointer<UnsafeMutablePointer<Int8>>.alloc(2) 
for (ix,s) in args.enumerate() { 
    cs[ix] = UnsafeMutablePointer<Int8>((s as NSString).UTF8String) 
} 
var cs2 : UnsafePointer<UnsafeMutablePointer<Int8>> = UnsafePointer(cs) 

當心; cs不包含副本。它的指針指向args中的字符串。