SQL查詢SUM從SELECT COUNT語句與UNION的表格

Question

我目前正在試圖總結一個MySQL語句的結果，它給了我幾個不同的表的行數。

我已經研究了關於這個問題的每一個stackoverflow的解決方案。不幸的是，我無法弄清楚我的案例的正確語法。

我的結果工作陳述不概括：

SET @shipmentId=456; 
SELECT 
     (SELECT COUNT(*) FROM Table1 WHERE ShipmentID = @shipmentId) 
     UNION ALL 
     (SELECT COUNT(*) FROM Table2 WHERE ShipmentID = @shipmentId) 
     UNION ALL 
     (SELECT COUNT(*) FROM Table3 WHERE ShipmentID = @shipmentId) 
     UNION ALL 
     (SELECT COUNT(*)FROM Table4 WHERE ShipmentID = @shipmentId) 
     UNION ALL 
     (SELECT COUNT(*)FROM Table5 WHERE ShipmentID = @shipmentId); 

在我看來，這應該是最近的一個正確的解決辦法，但我不知道（試過很多變種）：

SET @shipmentId=456; 
SELECT SUM(MeasuredValues) FROM 
    SELECT(
     (SELECT COUNT(*) FROM Table1 WHERE ShipmentID = @shipmentId) AS MeasuredValues 
     UNION ALL 
     (SELECT COUNT(*) FROM Table2 WHERE ShipmentID = @shipmentId) AS MeasuredValues 
     UNION ALL 
     (SELECT COUNT(*) FROM Table3 WHERE ShipmentID = @shipmentId) AS MeasuredValues 
     UNION ALL 
     (SELECT COUNT(*)FROM Table4 WHERE ShipmentID = @shipmentId) AS MeasuredValues 
     UNION ALL 
     (SELECT COUNT(*)FROM Table5 WHERE ShipmentID = @shipmentId) AS MeasuredValues) t1;  

在此先感謝您的幫助。

已經嘗試過以下鏈接： StackOverFlow Solution1

StackOverFlow Solution2

Answer 1

你可以只是簡單總結一下你的選擇：

SET @shipmentId=456; 
SELECT 
    (SELECT COUNT(*) FROM Table1 WHERE ShipmentID = @shipmentId) 
+ 
    (SELECT COUNT(*) FROM Table2 WHERE ShipmentID = @shipmentId) 
+ 
    (SELECT COUNT(*) FROM Table3 WHERE ShipmentID = @shipmentId) 
+ 
    (SELECT COUNT(*) FROM Table4 WHERE ShipmentID = @shipmentId) 
+ 
    (SELECT COUNT(*) FROM Table5 WHERE ShipmentID = @shipmentId);