在子查詢中的MySQL交集

Question

我正在嘗試爲表（公寓）創建過濾器，並通過apartsments_features表與apartment features建立多對多關係。

我想只包括全部的某些功能（在窗體上標記爲「是」）的公寓，但不包括具有任何其他功能（標記爲「否」）的公寓。我意識到太遲了，我不能在MySQL中使用INTERSECT或MINUS。

我有一個查詢，看起來像：

SELECT `apartments`.* FROM `apartments` WHERE `apartments`.`id` IN (
    SELECT `apartments`.`id` FROM `apartments` INTERSECT (
     SELECT `apartment_id` FROM `apartments_features` WHERE `feature_id` = 103 
INTERSECT SELECT `apartment_id` FROM `apartments_features` WHERE `feature_id` = 106 
    ) MINUS (
    SELECT `apartment_id` FROM `apartments_features` WHERE `feature_id` = 105 UNION 
    SELECT `apartment_id` FROM `apartments_features` WHERE `feature_id` = 107) 
) 
ORDER BY `apartments`.`name` ASC 

我敢肯定有辦法做到這一點，但此刻我的知識僅限於較簡單的左更小，右連接。

Answer 1

稍微不同的做這件事的方式：

select a.* 
from apartments a 
join apartments_features f1 
on a.apartment_id = f1.apartment_id and f1.feature_id in (103,106) -- applicable features 
where not exists 
(select null from apartments_features f2 
where a.apartment_id = f2.apartment_id and f2.feature_id in (105,107)) -- excluded features 
group by f1.apartment_id 
having count(*) = 2 -- number of applicable features 

Answer 2

你可以嘗試這樣的事：

SELECT apartment_id 
FROM 
(
    SELECT apartment_id 
    FROM apartments_features 
    WHERE feature_id IN (103, 106) 
    GROUP BY apartment_id 
    HAVING COUNT(*) = 2 
) T1 
LEFT JOIN 
(
    SELECT apartment_id 
    FROM apartments_features 
    WHERE feature_id IN (105, 107) 
) T2 
ON T1.apartment_id = T2.apartment_id 
WHERE T2.apartment_id IS NULL 

加入此查詢到公寓表的結果，以獲得名稱等