如何將查詢中的日期與上個月的日期進行比較

我想在oracle中爲其編寫一個查詢，我有一個表A，我想在課程中找到Transfer。在這個要求中，我必須將Feb數據與Jan比較，並生成另一個Y或N結果列。如何將查詢中的日期與上個月的日期進行比較

ID  Date   Course1 Course2 
123 01-JAN-2010 2000  3500 
123 01-FEB-2010 2000  3500 
123 01-MAR-2010 2500  3500 
123 01-APR-2010 2000  3500 
123 01-MAY-2010 2000  3000 
123 01-JUN-2010 2000  3500

要求：如果course1 <>比上月course1或 course2 <>比上月course2 則Y 其他ň

預期結果：

ID  Date   Course1 Course2 Transfer 
123 01-JAN-2010 2000  3500  
123 01-FEB-2010 2000  3500  N 
123 01-MAR-2010 2500  3500  Y 
123 01-APR-2010 2000  3500  Y 
123 01-MAY-2010 2000  3000  Y 
123 01-JUN-2010 2000  3000  N

我的查詢：

select a.ID, a.Date, a.Course1, a.Course2, 

case when (a.Course1 <> (select b.Course1 from TableA b where b.Date = add_months(a.Date-1) and b.ID = a.ID) or a.Course2 <> (select b.Course2 from TableA b where b.Date = add_months(a.Date-1) and b.ID = a.ID)) 
     then Y 
    else N 
end as Transfer 

from TableA a 
where a.ID = '123';

但是，這個查詢我收到錯誤或無效的參數....

需要幫助來糾正查詢或任何其他方法來獲得所需的結果。

感謝

添加------

，如果你可以使用這個數據，你會看到我得到了什麼問題

insert into TableA (idd, datee, course1, course2) values (123,'01-JAN-2010', 2000, NULL); 
insert into TableA (idd, datee, course1, course2) values (123,'01-FEB-2010', 2000, NULL); 
insert into TableA (idd, datee, course1, course2) values (123,'01-MAR-2010', 2000, NULL); 
insert into TableA (idd, datee, course1, course2) values (123,'01-APR-2010', 2000, NULL); 
insert into TableA (idd, datee, course1, course2) values (123,'01-MAY-2010', 2000, NULL); 
insert into TableA (idd, datee, course1, course2) values (123,'01-JUN-2010', 2000, NULL); 
insert into TableA (idd, datee, course1, course2) values (123,'01-JUL-2010', 2000, NULL); 
insert into TableA (idd, datee, course1, course2) values (123,'01-AUG-2010', 2000, NULL); 
insert into TableA (idd, datee, course1, course2) values (123,'01-SEP-2010', 2500, NULL); 
insert into TableA (idd, datee, course1, course2) values (123,'01-OCT-2010', 2000, NULL); 
insert into TableA (idd, datee, course1, course2) values (123,'01-NOV-2010', 2000, NULL); 
insert into TableA (idd, datee, course1, course2) values (123,'01-DEC-2010', 2000, NULL); 

insert into TableA (idd, datee, course1, course2) values (123,'01-JAN-2011', 2000, NULL); 
insert into TableA (idd, datee, course1, course2) values (123,'01-FEB-2011', 2000, NULL); 
insert into TableA (idd, datee, course1, course2) values (123,'01-MAR-2011', 2000, NULL); 
insert into TableA (idd, datee, course1, course2) values (123,'01-APR-2011', 2000, NULL); 
insert into TableA (idd, datee, course1, course2) values (123,'01-MAY-2011', 2000, NULL); 
insert into TableA (idd, datee, course1, course2) values (123,'01-JUN-2011', 2000, NULL); 
insert into TableA (idd, datee, course1, course2) values (123,'01-JUL-2011', 2000, NULL); 
insert into TableA (idd, datee, course1, course2) values (123,'01-AUG-2011', 2000, NULL); 
insert into TableA (idd, datee, course1, course2) values (123,'01-SEP-2011', 2500, NULL); 
insert into TableA (idd, datee, course1, course2) values (123,'01-OCT-2011', 2000, NULL); 
insert into TableA (idd, datee, course1, course2) values (123,'01-NOV-2011', 2000, NULL); 
insert into TableA (idd, datee, course1, course2) values (123,'01-DEC-2011', 2000, NULL); 

insert into TableA (idd, datee, course1, course2) values (123,'01-JAN-2012', 2000, NULL); 
insert into TableA (idd, datee, course1, course2) values (123,'01-FEB-2012', 2000, NULL); 
insert into TableA (idd, datee, course1, course2) values (123,'01-MAR-2012', 2000, NULL); 
insert into TableA (idd, datee, course1, course2) values (123,'01-APR-2012', 2000, NULL); 
insert into TableA (idd, datee, course1, course2) values (123,'01-MAY-2012', 2000, NULL); 
insert into TableA (idd, datee, course1, course2) values (123,'01-JUN-2012', 2000, NULL); 
insert into TableA (idd, datee, course1, course2) values (123,'01-JUL-2012', 2000, NULL); 
insert into TableA (idd, datee, course1, course2) values (123,'01-AUG-2012', 2000, NULL); 
insert into TableA (idd, datee, course1, course2) values (123,'01-SEP-2012', 2500, NULL); 
insert into TableA (idd, datee, course1, course2) values (123,'01-OCT-2012', 2000, NULL); 
insert into TableA (idd, datee, course1, course2) values (123,'01-NOV-2012', 2000, NULL); 
insert into TableA (idd, datee, course1, course2) values (123,'01-DEC-2012', 2000, NULL); 


insert into TableA (idd, datee, course1, course2) values (456,'01-JAN-2011', 2000, NULL); 
insert into TableA (idd, datee, course1, course2) values (456,'01-FEB-2011', 2000, NULL); 
insert into TableA (idd, datee, course1, course2) values (456,'01-MAR-2011', 2000, NULL); 
insert into TableA (idd, datee, course1, course2) values (456,'01-APR-2011', 2000, NULL); 
insert into TableA (idd, datee, course1, course2) values (456,'01-MAY-2011', 2000, NULL); 
insert into TableA (idd, datee, course1, course2) values (456,'01-JUN-2011', 2000, NULL); 
insert into TableA (idd, datee, course1, course2) values (456,'01-JUL-2011', 2000, NULL); 
insert into TableA (idd, datee, course1, course2) values (456,'01-AUG-2011', 2000, NULL); 
insert into TableA (idd, datee, course1, course2) values (456,'01-SEP-2011', 2500, NULL); 
insert into TableA (idd, datee, course1, course2) values (456,'01-OCT-2011', 2500, NULL); 
insert into TableA (idd, datee, course1, course2) values (456,'01-NOV-2011', 2500, NULL); 
insert into TableA (idd, datee, course1, course2) values (456,'01-DEC-2011', 2500, NULL); 

insert into TableA (idd, datee, course1, course2) values (456,'01-JAN-2012', 2500, NULL); 
insert into TableA (idd, datee, course1, course2) values (456,'01-FEB-2012', 2500, NULL); 
insert into TableA (idd, datee, course1, course2) values (456,'01-MAR-2012', 25000, NULL); 
insert into TableA (idd, datee, course1, course2) values (456,'01-APR-2012', 2000, NULL); 
insert into TableA (idd, datee, course1, course2) values (456,'01-MAY-2012', 2000, NULL); 
insert into TableA (idd, datee, course1, course2) values (456,'01-JUN-2012', 2000, NULL); 
insert into TableA (idd, datee, course1, course2) values (456,'01-JUL-2012', 2000, NULL); 
insert into TableA (idd, datee, course1, course2) values (456,'01-AUG-2012', 2000, NULL); 
insert into TableA (idd, datee, course1, course2) values (456,'01-SEP-2012', 2000, NULL); 
insert into TableA (idd, datee, course1, course2) values (456,'01-OCT-2012', 2000, NULL); 
insert into TableA (idd, datee, course1, course2) values (456,'01-NOV-2012', 2000, NULL); 
insert into TableA (idd, datee, course1, course2) values (456,'01-DEC-2012', 2000, NULL); 

insert into TableA (idd, datee, course1, course2) values (456,'01-JAN-2013', 2000, NULL); 
insert into TableA (idd, datee, course1, course2) values (456,'01-FEB-2013', 2000, NULL); 
insert into TableA (idd, datee, course1, course2) values (456,'01-MAR-2013', 2000, NULL); 
insert into TableA (idd, datee, course1, course2) values (456,'01-APR-2013', 2000, NULL); 
insert into TableA (idd, datee, course1, course2) values (456,'01-MAY-2013', 2000, NULL); 
insert into TableA (idd, datee, course1, course2) values (456,'01-JUN-2013', 2000, NULL); 
insert into TableA (idd, datee, course1, course2) values (456,'01-JUL-2013', 2000, NULL); 
insert into TableA (idd, datee, course1, course2) values (456,'01-AUG-2013', 2000, NULL); 
insert into TableA (idd, datee, course1, course2) values (456,'01-SEP-2013', 2500, NULL); 
insert into TableA (idd, datee, course1, course2) values (456,'01-OCT-2013', 2500, NULL); 
insert into TableA (idd, datee, course1, course2) values (456,'01-NOV-2013', 2500, NULL); 
insert into TableA (idd, datee, course1, course2) values (456,'01-DEC-2013', 2500, NULL);

我的查詢

select idd, datee, course1, course2, 
    case when (course1 <> lag(course1,1,course1) over (order by datee)) or 
     (course2 <> lag(course2,1,course2) over (order by datee)) 
    then 'Y' else 'N' end as transfer 
from tableA 
    where idd in ('123', '456') 
order by idd, datee;

來源

2016-11-08 Qasim0787

在oracle中有功能滯後。

select id, date, course1, course2, 
    case when (course1 <> lag(course1,1,course1) over (order by date)) or 
      (course2 <> lag(course2,1,course2) over (order by date)) 
    then 'Y' else 'N' end as transfer 
    from tableA 
    order by date;

編輯

select idd, datee, course1, course2, 
    case when (course1 <> lag(course1,1,course1) over (order by idd, datee)) or 
     (course2 <> lag(course2,1,course2) over (order by idd, datee)) 
    then 'Y' else 'N' end as transfer 
from tableA 
    where idd in ('123', '456') 
order by idd, datee;

來源

2016-11-08 20:38:27 Kacper

現在我需要在它的日期不同的日期序列的表來更新這個查詢多個ID。你可以請它的建議 – Qasim0787

@ Qasim0787但這個查詢適用於你在表中的所有日期。那麼有什麼問題？ – Kacper

我加了兩個id作爲例子。如果你可以創建表並嘗試你會看到我得到什麼問題。 – Qasim0787

如何將查詢中的日期與上個月的日期進行比較

回答

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