SQL語法錯誤 - haversine公式

Question

我使用Haversine formula

我的表結構的WordPress數據庫試圖get nearest places下面

帖子

+--------------+ 
| Field  | 
+--------------+ 
| ID   | 
| post_author | 
| post_title | 
| post_type | 
+--------------+ 

postmeta

+--------------+ 
| Field  | 
+--------------+ 
| meta_id  | 
| post_id  | 
| meta_key  | 
| meta_value | 
+--------------+ 

條

，並有記錄與meta_key值latitude和longitude

見answer to my previous question爲我用得到的緯度和經度的SQL。

SELECT p.ID, 
    p.post_title, 
    p.post_author, 
    max(case when pm.meta_key='latitude' then pm.meta_value end) latitude, 
    max(case when pm.meta_key='longitude' then pm.meta_value end) longitude 
FROM `wp_posts` p 
LEFT JOIN `wp_postmeta` pm 
    on p.ID=pm.post_id 
WHERE p.post_type='place' 
    AND (pm.meta_key='latitude' OR pm.meta_key='longitude') 
GROUP BY p.ID, p.post_title, p.post_author 
ORDER BY p.ID ASC 

現在我想結合上面的查詢到answer for this question

SELECT item1, item2, 
    (3959 * acos(cos(radians(37)) 
        * cos(radians(lat)) 
        * cos(radians(lng) 
         - radians(-122)) 
        + sin(radians(37)) 
        * sin(radians(lat)) 
       ) 
    ) AS distance 
FROM geocodeTable 
HAVING distance < 25 
ORDER BY distance LIMIT 0 , 20; 

以下信息由組合查詢

SELECT ID, 
    post_title, 
    post_author, 
    max(case when meta_key='latitude' then meta_value end) latitude, 
    max(case when meta_key='longitude' then meta_value end) longitude, 
    (3959 * acos(cos(radians(18.204540500000)) 
        * cos(radians(latitude)) 
        * cos(radians(longitude) 
         - radians(-66.450958500000)) 
        + sin(radians(18.204540500000) 
        * sin(radians(latitude)) 
       ) 
    ) AS distance 
FROM `wp_posts` 
LEFT JOIN `wp_postmeta` 
    on ID=post_id 
WHERE post_type='place' 
    AND (meta_key='latitude' OR meta_key='longitude') 
GROUP BY ID, post_title, post_author 
ORDER BY ID ASC 

但是這會產生語法錯誤

#1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'AS distance FROM `wp_posts` LEFT JOIN `wp_postmeta` on ID=post_id WHERE po' at line 13 

Answer 1

你缺少一個closi第一個sin()

(3959 * acos(cos(radians(18.204540500000)) 
        * cos(radians(latitude)) 
        * cos(radians(longitude) 
         - radians(-66.450958500000)) 
        + sin(radians(18.204540500000)) /* <--- here */ 
        * sin(radians(latitude)) 
      ) 
) AS distance 

雖然這是很難用肉眼發現納克)，我複製你的代碼到支持括號匹配文本編輯器中找到的。強烈建議使用一個，如果不是用於查詢開發和測試，則至少用於調試。

Answer 2

試試這個：

SELECT *, (3959 * ACOS(COS(RADIANS(18.204540500000)) 
        * COS(RADIANS(latitude)) 
        * COS(RADIANS(longitude) 
         - RADIANS(-66.450958500000)) 
        + SIN(RADIANS(18.204540500000)) 
        * SIN(RADIANS(latitude)) 
       ) 
    ) AS distance 
FROM 
(SELECT ID, 
    post_title, 
    post_author, 
    MAX(CASE WHEN meta_key='geo_latitude' THEN meta_value END) latitude, 
    MAX(CASE WHEN meta_key='geo_longitude' THEN meta_value END) longitude 
FROM `wp_posts` 
LEFT JOIN `wp_postmeta` 
    ON ID=post_id 
WHERE post_type='place' 
    AND (meta_key='geo_latitude' OR meta_key='geo_longitude') 
GROUP BY ID, post_title, post_author 
ORDER BY ID ASC) AS A