1
你好,我尋求幫助,看看我的查詢有什麼問題,它沒有返回來自table consulta的行數(number),其中userIDC等於表用戶的userID。以及來自表asesoria的userIDC的相同操作。Mysql SUM查詢沒有返回預期結果
SELECT c.*, SUM(IF(a.userIDA = c.userID , 1, 0)) AS count_asesoria, SUM(IF(s.userIDC = c.userID , 1, 0)) AS count_consulta
FROM users as c
LEFT JOIN consulta AS s ON s.userIDC = c.userID
LEFT JOIN asesoria AS a ON a.userIDA = c.userID
GROUP BY c.userID DESC
rigt現在returs兩個count_asesoria
和count_consulta
表用戶相同的結果:
userID | Data |
------------------
3 | content |
表CONSULTA
userIDC | Data |
------------------
3 | content |
3 | content |
所以count_consulta不得不返回2
您能否顯示一些示例數據以及您對查詢的期望結果? – dave