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我有這個程序,其中兩個線程等待相同的鎖股票對象並導致程序掛起。但是Thread1不會爲Thread2鎖而放棄,反之亦然。如果這不是死鎖,這種情況叫什麼?死鎖是否需要兩個線程等待每個其他資源?
public class DeadlockSimulator {
public static void main(String[] args) {
Stock st = new Stock();
Runnable p1 = new Producer(st);
Runnable c1 = new Consumer(st);
Thread t1 = new Thread(p1);
Thread t2 = new Thread(c1);
t1.start();
t2.start();
}
}
public class Producer implements Runnable{
private final Stock st;
public Producer(Stock st) {
this.st=st;
}
@Override
public void run() {
try{
while(true)
st.addStock(3);
}
catch(Exception e)
{
e.printStackTrace();
}
}
}
public class Stock {
private int qoh;
public Stock() {
}
public synchronized int getStock(int required) throws InterruptedException
{
int take=0;
if(qoh> required)
{
qoh=qoh-required;
take=required;
//notify();
}
else
{
wait();
}
return take;
}
public synchronized void addStock(int stocks) throws InterruptedException
{
if(qoh >7)
{
wait();
}
else
{
qoh=qoh+stocks;
System.out.println("Current Stock"+ qoh);
// notify();
}
}
public int getorderLevel()
{
return this.qoh;
}
}
public class Consumer implements Runnable {
private final Stock st;
public Consumer(Stock st) {
this.st = st;
}
@Override
public void run() {
try {
while (true) {
int got = st.getStock(5);
System.out.println("Got =" + got);
}
} catch (Exception e) {
e.printStackTrace();
}
}
}
這是一個等待* * single *資源的兩個線程的例子,'Stock.'不是死鎖。 – EJP
程序掛起,因爲你在run()中有一個無限循環 –