Java SQL錯誤1064

我遇到了一些簡單的代碼問題，但無法弄清楚我究竟做了什麼錯誤。以下是我的代碼：Java SQL錯誤1064

String userName = "username"; 
     String password = "password"; 
     String url = "jdbc:mysql://computername/proejct"; 
     Connection conn=null; 
     String value="some_value"; 

     try 
     { 
      Class.forName("com.mysql.jdbc.Driver").newInstance(); 
      conn = DriverManager.getConnection(url, userName, password); 

      String query1= "SELECT * FROM table WHERE column_Name=?"; 
      PreparedStatement psmt1 = conn.prepareStatement(query1); 
      psmt1.setString(1, value); 

      Boolean count=psmt1.execute(query1); 
      if(count==false) 
      { 
       //do something 
      } 
      psmt1.close(); 

     } 
     catch (Exception e) 
     { 
      e.printStackTrace(); 
     }

這是我收到的錯誤：

[email protected]: SELECT * FROM source2 WHERE File_Name='Messages.java' 
com.mysql.jdbc.exceptions.jdbc4.MySQLSyntaxErrorException: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '?' at line 1 
    at sun.reflect.GeneratedConstructorAccessor3.newInstance(Unknown Source) 
    at sun.reflect.DelegatingConstructorAccessorImpl.newInstance(Unknown Source) 
    at java.lang.reflect.Constructor.newInstance(Unknown Source) 
    at com.mysql.jdbc.Util.handleNewInstance(Util.java:409) 
    at com.mysql.jdbc.Util.getInstance(Util.java:384) 
    at com.mysql.jdbc.SQLError.createSQLException(SQLError.java:1054) 
    at com.mysql.jdbc.MysqlIO.checkErrorPacket(MysqlIO.java:3566) 
    at com.mysql.jdbc.MysqlIO.checkErrorPacket(MysqlIO.java:3498) 
    at com.mysql.jdbc.MysqlIO.sendCommand(MysqlIO.java:1959) 
    at com.mysql.jdbc.MysqlIO.sqlQueryDirect(MysqlIO.java:2113) 
    at com.mysql.jdbc.ConnectionImpl.execSQL(ConnectionImpl.java:2562) 
    at com.mysql.jdbc.ConnectionImpl.execSQL(ConnectionImpl.java:2512) 
    at com.mysql.jdbc.StatementImpl.execute(StatementImpl.java:781) 
    at com.mysql.jdbc.StatementImpl.execute(StatementImpl.java:624) 
    at SearchAndUpdate.recursiveUpdate(SearchAndUpdate.java:98) 
    at SearchAndUpdate.recursiveUpdate(SearchAndUpdate.java:115) 
    at SearchAndUpdate.recursiveUpdate(SearchAndUpdate.java:115) 
    at SearchAndUpdate.recursiveUpdate(SearchAndUpdate.java:115) 
    at SearchAndUpdate.recursiveUpdate(SearchAndUpdate.java:115) 
    at SearchAndUpdate.recursiveUpdate(SearchAndUpdate.java:115) 
    at SearchAndUpdate.recursiveUpdate(SearchAndUpdate.java:115) 
    at SearchAndUpdate.recursiveUpdate(SearchAndUpdate.java:115) 
    at SearchAndUpdate.recursiveUpdate(SearchAndUpdate.java:115) 
    at SearchAndUpdate.recursiveTraversal(SearchAndUpdate.java:55) 
    at SearchAndUpdate.main(SearchAndUpdate.java:40)

我做得不對的preparedstements？

我打印出來的準備語句，這是它的樣子： SELECT * FROM源2 WHERE列名= 'Messages.java'

來源

2011-06-23 sap

這是'字符串QUERY1 = 「SELECT * FROM表WHERE列名=？」;'你的實際類的聲明？您的錯誤消息'SELECT * FROM source2 WHERE File_Name ='Messages.java'顯示不同的語句。 –

基於這一行：

check the manual that corresponds to your MySQL server version for the right syntax to use near '?' at line 1

它看起來像你的陳述沒有被準備。 ?正在發送到MySQL。

我想這：

Boolean count=psmt1.execute(query1);

應該是（編輯）

ResultSet count=psmt1.executeQuery();

來源

2011-06-23 16:41:29 NullRef

也只是想添加你的變量不應該是一個布爾值它應該是一個ResultSet，因爲你正在做一個選擇語句。我不知道這是否會導致錯誤，但應該考慮到 – RMT

@RMT您是對的。 – NullRef

謝謝。有效。 – sap

Java SQL錯誤1064

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