你可以簡單地使用:
with curricul as
(select 1 classid, 'Math' class from dual union all
select 2, 'Literature' from dual
)
,
student as
(select 1 id, 1 classid, 'male' gender, 1 race, 1 eth from dual union all
select 2, 1, 'female', 1, 2 from dual union all
select 3, 1, 'male' , 3, 1 from dual union all
select 4, 1, 'male' , 5, 7 from dual union all
select 5, 1, 'female', 4, 8 from dual union all
select 6, 1, 'male' , 1, 6 from dual union all
select 7, 2, 'female', 3, 4 from dual union all
select 8, 2, 'female', 1, 1 from dual union all
select 9, 2, 'female', 7, 9 from dual union all
select 10, 2, 'male' , 9, 1 from dual union all
select 11, 2, 'female', 8, 1 from dual
)
select s.classid, curricul.class
,count(s.gender) as count_gender
,sum(case when gender = 'male' then 1 else 0 end) as count_male
,sum(case when gender = 'female' then 1 else 0 end) as count_female
,count(s.race) as count_race
,count(s.eth) as count_ethnicity
from student s
inner join curricul
on s.classid = curricul.classid
group by s.classid, curricul.class ;
你還沒有告訴我們你從工作中的數據,表結構,或者是與查詢你」發生什麼(這是舊式的語法;與ANSI加入它會更明顯你缺少連接條件)。爲什麼h您是否包含圖片而不是文字,顯示您想要的內容?它看起來並不像你想旋轉一樣。你是否正在尋找'count(case ... end)'來獲得男性/女性的數字? –