如何在foreach循環PHP中用if語句更改圖像？

Question

我正在使用CMS ProscessWire。

我有一個工作的foreach循環，顯示孩子的標題和5個鏈接。鏈接顯示爲圖像。這工作完美無瑕。但是，我想要一個空白的鏈接黑白圖像來顯示沒有鏈接。所以我做了一個if語句。但是，當我把if語句放在循環中時，顯示的唯一子節點就是具有空鏈接的節點。

有誰知道tot如何解決這個問題？我認爲這是一件簡單的事情，但無法弄清楚。

PHP-代碼：

$rdio='rdio.png'; 
    $itunes='itunes.png'; 
    $xbox='xbox.png'; 
    $googleplay='googleplay.png'; 
    $spotify='spotify.png'; 
    $deezer='deezer.png'; 

    foreach($page->children as $child) 

    if(!$child->Rdio) { 
$rdio='rdiog.png'; 
    } 
    else 
    { 
    $rdio='rdio.png'; 
    } 

     echo "<ul style='background-color:#CCC;'>"."<li><h1>{$child->title}</h1></li>".<li><a class='rdio' href='{$child->Rdio}'><img src='../site/templates/img/$rdio' alt='rdio'/></a></li>"."<li><a class='itunes' href='{$child->iTunes}'><img src='../site/templates/img/$itunes' alt='itunes'/></a></li>"."<li><a class='xbox' href='{$child->Xbox}'><img src='../site/templates/img/$xbox' alt='xbox'/></a></li>"."<li><a class='googleplay' href='{$child->GooglePlay}'><img src='../site/templates/img/$googleplay' alt='googleplay'/></li>"."<li><a class='spotify' href='{$child->Spotify}'><img src='../site/templates/img/$spotify' alt='spotify'/></a></li>"."<li><a class='deezer' href='{$child->Deezer}'><img src='../site/templates/img/$deezer' alt='deezer'/></a></li>"."</ul><br/>";    

Answer 1

你缺少周圍foreach一些括號，只有執行以下IF語句，並繼續打印出一個元素在頁面上。爲了解決這個問題，只需添加括號foreach循環是這樣的：

$rdio='rdio.png'; 
    $itunes='itunes.png'; 
    $xbox='xbox.png'; 
    $googleplay='googleplay.png'; 
    $spotify='spotify.png'; 
    $deezer='deezer.png'; 

    foreach($page->children as $child) { 

    if(!$child->Rdio) { 
$rdio='rdiog.png'; 
    } 
    else 
    { 
    $rdio='rdio.png'; 
    } 

     echo "<ul style='background-color:#CCC;'>"."<li><h1>{$child->title}</h1></li>".<li><a class='rdio' href='{$child->Rdio}'><img src='../site/templates/img/$rdio' alt='rdio'/></a></li>"."<li><a class='itunes' href='{$child->iTunes}'><img src='../site/templates/img/$itunes' alt='itunes'/></a></li>"."<li><a class='xbox' href='{$child->Xbox}'><img src='../site/templates/img/$xbox' alt='xbox'/></a></li>"."<li><a class='googleplay' href='{$child->GooglePlay}'><img src='../site/templates/img/$googleplay' alt='googleplay'/></li>"."<li><a class='spotify' href='{$child->Spotify}'><img src='../site/templates/img/$spotify' alt='spotify'/></a></li>"."<li><a class='deezer' href='{$child->Deezer}'><img src='../site/templates/img/$deezer' alt='deezer'/></a></li>"."</ul><br/>";  

Answer 2

嘗試使用empty方法：

$rdio='rdio.png'; 
$itunes='itunes.png'; 
$xbox='xbox.png'; 
$googleplay='googleplay.png'; 
$spotify='spotify.png'; 
$deezer='deezer.png'; 

foreach($page->children as $child) { 

if(empty($child->Rdio)) { 
$rdio='rdiog.png'; 
} 
else 
{ 
$rdio='rdio.png'; 
} 

    echo "<ul style='background-color:#CCC;'>"."<li><h1>{$child->title}</h1></li>".<li><a class='rdio' href='{$child->Rdio}'><img src='../site/templates/img/$rdio' alt='rdio'/></a></li>"."<li><a class='itunes' href='{$child->iTunes}'><img src='../site/templates/img/$itunes' alt='itunes'/></a></li>"."<li><a class='xbox' href='{$child->Xbox}'><img src='../site/templates/img/$xbox' alt='xbox'/></a></li>"."<li><a class='googleplay' href='{$child->GooglePlay}'><img src='../site/templates/img/$googleplay' alt='googleplay'/></li>"."<li><a class='spotify' href='{$child->Spotify}'><img src='../site/templates/img/$spotify' alt='spotify'/></a></li>"."<li><a class='deezer' href='{$child->Deezer}'><img src='../site/templates/img/$deezer' alt='deezer'/></a></li>"."</ul><br/>";