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我想編寫一個java程序,它將用戶作爲輸入並在OpenDS或LDAP中搜索,並告訴用戶屬於哪個特定的組。用戶可以是多個組的一部分,我想知道用戶所屬的所有組。java程序告訴用戶屬於哪個組在LDAP中
此外,我有超過800個用戶屬於Excel文件中的各個組。我想查詢他們所有人。這裏是查詢下面這是給我一個用戶所需的結果。
ldapsearch --hostname myhost --port 3890 --baseDN s=s-i -D cn=Manager -w ldapadmin --searchScope sub "(&(objectclass=groupOfUniqueNames)(uniqueMember=cn=Kevin,ou=standard,ou=users,ou=tpc,dc=intra))"
現在我想爲此編寫一個java代碼。 下面是Java代碼我與不同的用戶嘗試: - 上述
import java.io.BufferedReader;
import java.io.File;
import java.io.FileReader;
import java.util.Hashtable;
import java.util.Enumeration;
import javax.naming.*;
import javax.naming.directory.*;
public class LDAP_Reader_MultiUser1 {
public static String INITCTX = "com.sun.jndi.ldap.LdapCtxFactory";
public static String MY_HOST = "ldap://singh.plm.com:3890";
public static String MY_SEARCHBASE = "cn=Public,x=x-y,ou=people,cn=UserBAse_8.0,cn=Application Services,o=x-y";
public static String MY_FILTER = "(&(objectclass=groupOfUniqueNames)(uniqueMember=";
public static String MGR_DN = "cn=Manager";
public static String MGR_PW = "ldapadmin";
public static void main(String[] args) {
String[] MY_FILTER2=null;
try{
String fileName="C:\\report\\report.txt";
FileReader inputFile = new FileReader(fileName);
BufferedReader bufferReader = new BufferedReader(inputFile);
String line;
int i=0;
while ((line = bufferReader.readLine()) != null)
{
System.out.println("Reading text file");
MY_FILTER2[i]=line;
i++;
}
int j=i;
while(j>0)
{
System.out.println("MAking my_filter_final");
String MY_FILTER_Final=MY_FILTER+MY_FILTER2[i]+"))\"";
i--;
Hashtable env = new Hashtable();
env.put(Context.INITIAL_CONTEXT_FACTORY,INITCTX);
env.put(Context.PROVIDER_URL,MY_HOST);
env.put(Context.SECURITY_AUTHENTICATION,"simple");
env.put(Context.SECURITY_PRINCIPAL,MGR_DN);
env.put(Context.SECURITY_CREDENTIALS,MGR_PW);
DirContext ctx = new InitialDirContext(env);
SearchControls constraints = new SearchControls();
constraints.setSearchScope(SearchControls.SUBTREE_SCOPE);
//performs the actual search
//We give it a searchbase, a filter and the contraints containing the scope
//of the search
NamingEnumeration results = ctx.search(MY_SEARCHBASE,MY_FILTER_Final,constraints);
//now stop through the search results
while(results != null && results.hasMore()){
SearchResult sr = (SearchResult)results.next();
String dn = sr.getName();
System.out.println("Distinguished name is "+dn);
Attributes attrs = sr.getAttributes();
NamingEnumeration ne = attrs.getAll();
while(ne.hasMoreElements()) {
Attribute attr = (Attribute) ne.next();
String attrID = attr.getID();
System.out.println(attrID+" :");
Enumeration vals = attr.getAll();
while(vals.hasMoreElements()) {
System.out.println("\t"+vals.nextElement());
}
}
System.out.println("\n");
}
}
}catch(Exception ex){
ex.printStackTrace();
System.exit(1);
}
}
}
的代碼提供了以下錯誤輸出。
Reading text file
java.lang.NullPointerException
at com.LDAP_Reader_MultiUser1.main(LDAP_Reader_MultiUser1.java:32)
目前使用OpenDS的和開放的LDAP
無雜念,沒有閒聊(讀作[幫助→遊(http://stackoverflow.com/tour)),因此離開了感謝並從任何好問題中提出關於緊迫性的陳述。 – Anthon 2015-03-19 07:09:39
我做了一個LDAP查詢它搜索用戶屬於哪個組。 – 2015-03-20 08:34:29
解決了空指針異常的問題但它沒有返回多個組。 – 2015-03-24 12:35:52