1
在我的控制器之一,我有以下幾點:Laravel通過中間型號預先加載
return Lot::with(array('region', 'territory', 'manager')) -> get();
這完美的作品,並返回如下:
Array
(
[0] => stdClass Object
(
[id] => 1
[region_id] => 3
[territory_id] => 2
[state_id] => 5
[manager_id] => 2
[lot_num] => 0
[lot_type] => managed
[name] => Some Name
[address_1] => Some Address
[address_2] =>
[address_3] =>
[city] => Some City
[zip] => 00000
[opened_at] =>
[deleted_at] =>
[created_at] => 2014-11-06 00:49:39
[updated_at] => 2014-11-06 00:49:39
[region] => stdClass Object
(
[id] => 3
[name] => Corporate
[deleted_at] =>
[created_at] => 2014-11-06 00:49:39
[updated_at] => 2014-11-06 00:49:39
)
[territory] => stdClass Object
(
[id] => 2
[name] => Corporate
[deleted_at] =>
[created_at] => 2014-11-06 00:49:39
[updated_at] => 2014-11-06 00:49:39
)
[manager] => stdClass Object
(
[id] => 2
[email] => [email protected]
[active] => 1
[last_login] =>
[created_at] => 2014-11-06 00:49:39
[updated_at] =>
[deleted_at] =>
)
)
)
我的「經理」的方法該地塊類有如下關係:
return $this -> belongsTo('User');
我的用戶類別上有以下方法:
public function profile(){
return $this -> hasOne('Profile');
}
現在,終於我的問題:)是否有可能急於加載該用戶通過預先加載,我在第一個代碼剪斷做我的很多課的個人資料?我想要做到的是有我的「經理」對象的回報是這個樣子:
[manager] => stdClass Object
(
[id] => 2
[email] => [email protected]
[active] => 1
[last_login] =>
[created_at] => 2014-11-06 00:49:39
[updated_at] =>
[deleted_at] =>
[profile] => stdClass Object
(
[id] => 5
[first_name] => Test
[last_name] => Tester
...
)
)
真棒...謝謝! – dxhans5 2014-11-06 17:50:30
億上傳...謝謝Razor – dangel 2015-09-06 00:42:15