SQL查詢排除值

我已經得到了我在其中要排除特定值（在這個例子中「馬太福音」）查詢SQL查詢排除值

的查詢工作不完美子查詢它：

SELECT test.SAME , test.Nationality, test.Name, coalesce(test2.Job,'')jobb 
    FROM test 
    LEFT JOIN test2 
    ON test.noID=test2.noID 
    WHERE test.SAME = 555 and test.Name NOT IN (
               SELECT * 
               FROM test 
               WHERE test.NAME = "Mat" 
              ) 
    group by SAME , name 
    order by same desc

這裏舉例：

http://www.sqlfiddle.com/#!2/1f1fb/28

來源

2014-04-13 user3066588

http://www.sqlfiddle.com/#!2/1f1fb/34 – Mihai

這不起作用，因爲如果您的子查詢是'SELECT test.Name FROM'，比較'test.Name'和'SELECT *' '它的工作。順便說一句，正如人們建議直接使用'！='或'<>'或'NOT LIKE'來排除沒有子查詢的名稱;） – Ryx5

在你的where子句中嵌套select語句是不好的做法。您應該使用連接並根據where子句中的匹配進行排除。 –

你可以做到這一點，如果你想與墊匹配確切名稱：

SELECT test.SAME , test.Nationality, test.Name, coalesce(test2.Job,'')jobb 
    FROM test 
    LEFT JOIN test2 
    ON test.noID=test2.noID 
    WHERE test.SAME = 555 and test.Name != "Mat" 

group by SAME , name 
    order by same desc

如果要排除所有包含墊，則：如果你想排除

SELECT test.SAME , test.Nationality, test.Name, coalesce(test2.Job,'')jobb 
     FROM test 
     LEFT JOIN test2 
     ON test.noID=test2.noID 
     WHERE test.SAME = 555 and test.Name NOT LIKE '%Mat%' 

    group by SAME , name 
     order by same desc

始於墊，則：

SELECT test.SAME , test.Nationality, test.Name, coalesce(test2.Job,'')jobb 
      FROM test 
      LEFT JOIN test2 
      ON test.noID=test2.noID 
      WHERE test.SAME = 555 and test.Name NOT LIKE 'Mat%' 

     group by SAME , name 
      order by same desc

來源

2014-04-13 16:30:42

您可以使用NOT LIKEstatement：

SELECT test.SAME , test.Nationality, test.Name, coalesce(test2.Job,'')jobb 
    FROM test 
    LEFT JOIN test2 
    ON test.noID=test2.noID 
    WHERE test.SAME = 555 and test.Name not like 'Mat' 
    group by SAME , name 
    order by same desc

SQLFiddle

還是<>或!=operator：

SELECT test.SAME , test.Nationality, test.Name, coalesce(test2.Job,'')jobb 
    FROM test 
    LEFT JOIN test2 
    ON test.noID=test2.noID 
    WHERE test.SAME = 555 and test.Name <> 'Mat' 
    group by SAME , name 
    order by same desc

SQLFiddle

來源

2014-04-13 16:31:16 StarsSky

作品完美，謝謝！ – user3066588

您的查詢應該是： -

SELECT test.SAME , test.Nationality, test.Name, coalesce(test2.Job,'')jobb 
    FROM test 
    LEFT JOIN test2 
    ON test.noID=test2.noID 
    WHERE test.SAME = 555 and test.Name NOT IN (
              SELECT NAME 
              FROM test 
              WHERE test.NAME = "Mat" 
             ) 
    group by SAME , name 
    order by same desc

來源

2014-04-13 16:42:00 Saurabh

子QUER y不會工作，因爲你在子查詢中給了select *，但在外部查詢中你只有一個單獨的列來匹配哪個是test.Name。如果你將子查詢（SELECT test.Name FROM test WHERE test.NAME =「Mat」）放在一起，那麼整個查詢就可以工作。但順便說一下，這裏不需要子查詢來獲得您想要的結果。

來源

2014-04-13 16:46:00

SQL查詢排除值

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