根據列值對分層SQL行進行排序

Question

我正在使用以下SQL來生成分層數據並努力解決如何讓孩子按排序順序ID值進行排序。任何意見如何將不勝感激。請注意，這不是我的SQL，它來自我修改的OpenCart的類別列表頁面。我嘗試將排序順序添加到一些地方，但似乎沒有任何區別。我想輸出是表明是

| PAGE_ID |      NAME | PARENT_ID | SORT_ORDER | 
|---------|----------------------------|-----------|------------| 
|  75 |      Index4 |   0 |   -7 | 
|  60 |      Index |   0 |   0 | 
|  68 |    Index > Sub6 |  60 |   -6 | 
|  61 |    Index > Sub1 |  60 |   1 | 
|  65 | Index > Sub1 > SubSub2 |  61 |   4 | 
|  64 | Index > Sub1 > SubSub1 |  61 |   6 | 
|  67 |    Index > Sub5 |  60 |   1 | 
|  62 |    Index > Sub2 |  60 |   2 | 
|  63 |    Index > Sub3 |  60 |   5 | 
|  69 | Index > Sub3 > SubSub3 |  63 |   1 | 
|  71 | Index > Sub3 > SubSub5 |  63 |   2 | 
|  72 | Index > Sub3 > SubSub4 |  63 |   5 | 
|  70 | Index > Sub3 > SubSub6 |  63 |   9 | 
|  66 |    Index > Sub4 |  60 |   7 | 
|  74 |      Index3 |   0 |   1 | 
|  73 |      Index2 |   0 |   4 | 

注意，樹的每個子集是基於sort_order列單獨訂購，所以對於Index排序順序會對Sub1，Sub2或Sub3並沒有影響無那些會對SubSub1，SubSub2或SubSub3

Here's the SQL Fiddle

DROP TABLE IF EXISTS `oc_page`; 
CREATE TABLE `oc_page` (
    `page_id` int(11) NOT NULL AUTO_INCREMENT, 
    `parent_id` int(11) NOT NULL DEFAULT '0', 
    `sort_order` int(3) NOT NULL DEFAULT '0', 
    `status` tinyint(1) NOT NULL, 
    `date_added` datetime NOT NULL, 
    `date_modified` datetime NOT NULL, 
    PRIMARY KEY (`page_id`), 
    KEY `parent_id` (`parent_id`) 
) ENGINE=MyISAM AUTO_INCREMENT=66 DEFAULT CHARSET=utf8; 

BEGIN; 
INSERT INTO `oc_page` VALUES ('60', '0', '0', '1', '2014-10-16 02:49:41', '2014-10-17 02:03:15'), ('61', '60', '1', '1', '2014-10-17 02:03:02', '2014-10-17 03:17:20'), ('62', '60', '2', '1', '2014-10-17 02:18:59', '2014-10-17 03:16:20'), ('63', '60', '3', '1', '2014-10-17 02:23:27', '2014-10-17 03:16:49'), ('64', '61', '6', '1', '2014-10-17 03:17:49', '2014-10-17 03:17:58'), ('65', '61', '4', '1', '2014-10-17 03:18:36', '2014-10-17 03:18:36'); 
COMMIT; 

DROP TABLE IF EXISTS `oc_page_description`; 
CREATE TABLE `oc_page_description` (
    `page_id` int(11) NOT NULL, 
    `language_id` int(11) NOT NULL, 
    `name` varchar(255) NOT NULL, 
    `description` text NOT NULL, 
    `meta_title` varchar(255) NOT NULL, 
    `meta_description` varchar(255) NOT NULL, 
    `meta_keyword` varchar(255) NOT NULL, 
    PRIMARY KEY (`page_id`,`language_id`), 
    KEY `name` (`name`) 
) ENGINE=MyISAM DEFAULT CHARSET=utf8; 

BEGIN; 
INSERT INTO `oc_page_description` VALUES ('60', '1', 'Index', '<p>Test</p>', 'Test', '', ''), ('61', '1', 'Sub1', 'Sub1', 'Sub1', '', ''), ('64', '1', 'SubSub1', 'SubSub1', 'SubSub1', '', ''), ('65', '1', 'SubSub2', 'SubSub2', 'SubSub2', '', ''), ('62', '1', 'Sub2', 'Sub2', 'Sub2', '', ''), ('63', '1', 'Sub3', 'Sub3', 'Sub3', '', ''); 
COMMIT; 

DROP TABLE IF EXISTS `oc_page_path`; 
CREATE TABLE `oc_page_path` (
    `page_id` int(11) NOT NULL, 
    `path_id` int(11) NOT NULL, 
    `level` int(11) NOT NULL, 
    PRIMARY KEY (`page_id`,`path_id`) 
) ENGINE=MyISAM DEFAULT CHARSET=utf8; 

BEGIN; 
INSERT INTO `oc_page_path` VALUES ('60', '60', '0'), ('61', '61', '1'), ('61', '60', '0'), ('62', '62', '1'), ('62', '60', '0'), ('63', '63', '1'), ('63', '60', '0'), ('64', '64', '2'), ('64', '60', '0'), ('64', '61', '1'), ('65', '60', '0'), ('65', '61', '1'), ('65', '65', '2'); 
COMMIT; 

DROP TABLE IF EXISTS `oc_page_to_store`; 
CREATE TABLE `oc_page_to_store` (
    `page_id` int(11) NOT NULL, 
    `store_id` int(11) NOT NULL, 
    PRIMARY KEY (`page_id`,`store_id`) 
) ENGINE=MyISAM DEFAULT CHARSET=utf8; 

BEGIN; 
INSERT INTO `oc_page_to_store` VALUES ('60', '0'), ('61', '0'), ('62', '0'), ('63', '0'), ('64', '0'), ('65', '0'); 
COMMIT; 

的效果

查詢1：

SELECT pp.page_id AS page_id, 
     GROUP_CONCAT(pd1.name 
        ORDER BY pp.level SEPARATOR ' > ') AS name, 
     p1.parent_id, 
     p1.sort_order 
FROM oc_page_path pp 
LEFT JOIN oc_page p1 ON (pp.page_id = p1.page_id) 
LEFT JOIN oc_page p2 ON (pp.path_id = p2.page_id) 
LEFT JOIN oc_page_description pd1 ON (pp.path_id = pd1.page_id) 
LEFT JOIN oc_page_description pd2 ON (pp.page_id = pd2.page_id) 
WHERE pd1.language_id = '1' 
    AND pd2.language_id = '1' 
GROUP BY pp.page_id 
ORDER BY name ASC LIMIT 0,20 

Results：

注：這是我加入到澄清問題更多虛擬數據。小提琴將顯示顯著較少的數據

| PAGE_ID |      NAME | PARENT_ID | SORT_ORDER | 
|---------|----------------------------|-----------|------------| 
|  60 |      Index |   0 |   0 | 
|  61 |    Index > Sub1 |  60 |   1 | 
|  64 | Index > Sub1 > SubSub1 |  61 |   6 | 
|  65 | Index > Sub1 > SubSub2 |  61 |   4 | 
|  62 |    Index > Sub2 |  60 |   2 | 
|  63 |    Index > Sub3 |  60 |   5 | 
|  69 | Index > Sub3 > SubSub3 |  63 |   1 | 
|  70 | Index > Sub3 > SubSub6 |  63 |   9 | 
|  71 | Index > Sub3 > SubSub5 |  63 |   2 | 
|  72 | Index > Sub3 > SubSub4 |  63 |   5 | 
|  66 |    Index > Sub4 |  60 |   7 | 
|  67 |    Index > Sub5 |  60 |   1 | 
|  68 |    Index > Sub6 |  60 |   -6 | 
|  73 |      Index2 |   0 |   4 | 
|  74 |      Index3 |   0 |   1 | 
|  75 |      Index4 |   0 |   -7 | 

Answer 1

你可以簡單地使用子查詢離婚從裏面ORDER顯示ORDER：

SELECT * 
FROM (
     SELECT pp.page_id AS page_id, 
      GROUP_CONCAT(pd1.name 
          ORDER BY pp.level SEPARATOR ' > ') AS name, 
      p1.parent_id, 
      p1.sort_order 
     FROM oc_page_path pp 
     LEFT JOIN oc_page p1 ON (pp.page_id = p1.page_id) 
     LEFT JOIN oc_page p2 ON (pp.path_id = p2.page_id) 
     LEFT JOIN oc_page_description pd1 ON (pp.path_id = pd1.page_id) 
     LEFT JOIN oc_page_description pd2 ON (pp.page_id = pd2.page_id) 
     WHERE pd1.language_id = '1' 
     AND pd2.language_id = '1' 
     GROUP BY pp.page_id 
     ORDER BY name ASC LIMIT 0,20 
     ) sub 
ORDER BY Sort_Order 

演示：SQL Fiddle

注：我假設你需要內部ORDER BY由於LIMIT，因爲如果不是，你可以只是ORDER BY Sort_Order。

Answer 2

如果我正確理解你的問題，你可以通過排序順序由第一，然後才能砍名稱，訂單的最後一部分：

select page_id, parent_id, sort_order, name 
    , substr(name, 1, length(name) - locate(' > ', reverse(name))) as path 
from (
    SELECT pp.page_id AS page_id 
     , GROUP_CONCAT(pd1.name ORDER BY pp.level SEPARATOR ' > ') AS name 
     , p1.parent_id, p1.sort_order 
    FROM oc_page_path pp 
    LEFT JOIN oc_page p1 
     ON pp.page_id = p1.page_id 
    LEFT JOIN oc_page p2 
     ON pp.path_id = p2.page_id 
    LEFT JOIN oc_page_description pd1 
     ON pp.path_id = pd1.page_id 
    LEFT JOIN oc_page_description pd2 
     ON pp.page_id = pd2.page_id ' 
    WHERE pd1.language_id = '1' 
     AND pd2.language_id = '1' 
    GROUP BY pp.page_id, p1.parent_id, p1.sort_order 
) as t 
order by path, sort_order; 

+---------+-----------+------------+----------------------------+-------------------+ 
| page_id | parent_id | sort_order | name      | path    | 
+---------+-----------+------------+----------------------------+-------------------+ 
|  60 |   0 |   0 | Index      | Index    | 
|  61 |  60 |   1 | Index > Sub1    | Index >   | 
|  62 |  60 |   2 | Index > Sub2    | Index >   | 
|  63 |  60 |   3 | Index > Sub3    | Index >   | 
|  65 |  61 |   4 | Index > Sub1 > SubSub2 | Index > Sub1 > | 
|  64 |  61 |   6 | Index > Sub1 > SubSub1 | Index > Sub1 > | 
+---------+-----------+------------+----------------------------+-------------------+