0
(SELECT dtable.*, new_apps.top as t1 FROM app_detailsvvv as dtable INNER JOIN new_apps ON
new_apps.trackId=dtable.trackId WHERE (SELECT COUNT(*) AS c FROM compositions as dtablev
WHERE parent='169469' AND trackId=dtable.trackId AND new_apps.top > 0)>0) UNION
(SELECT *, 301 FROM app_detailsvvv as dtable WHERE (SELECT COUNT(*) AS c FROM compositions
as dtablev WHERE parent='169469' AND trackId=dtable.trackId)>0) ORDER BY t1 ASC, trackName
ASC LIMIT 0,12
這個查詢給我帶來了重複,我怎麼能通過trackId對它進行分組?如何按順序排序,通過有點複雜的mysql查詢
在工會中的兩個查詢都有字段trackId選擇,但我不能按照訂單進行分組 – lbennet
您不能同時進行分組和排序,因爲group by會根據訂單的順序進行排序您從左至右選擇。只需使用group – Fandango68