PHP類沒有任何返回

Question

我只是PHP OOP的初學者。我有一個類和輸出是空的：

$test = new form('name1', 'passw2'); 
     $test->getName(); 

和類：

<?php 
class form 
{ 
    protected $username; 
    protected $password; 
    protected $errors = array(); 

    function _construct($username, $password){ 
     $this->username=$username; 
     $this->password=$password; 
    } 

    public function getsomething() { 
     echo '<br>working'. $this->getn() . '<-missed'; 
    } 

    public function getName(){ 

    return $this->getsomething(); 

    } 
    public function getn() { 
     return $this->username; 
    } 
} 
?> 

和輸出，而不只是用戶名文本： POST工作 工作< -missed 哪裏NAME1？

Answer 1

我體改你的代碼了一下，加了一些例子來玩弄。 這應該讓你開始。

class form 
{ 
    protected $username; 
    protected $password; 
    protected $errors = array(); 

    // construct is a magic function, two underscores are needed here 

    function __construct($username, $password){ 
     $this->username = $username; 
     $this->password = $password; 
    } 

    // functions starting with get are called Getters 
    // they are accessor functions for the class property of the same name 

    public function getPassword(){ 
     return $this->password; 
    } 

    public function getUserName() { 
     return $this->username; 
    } 

    public function render() { 
     echo '<br>working:'; 
     echo '<br>Name: ' . $this->username;  // using properties directly 
     echo '<br>Password:' . $this->password; // not the getters 
    } 
} 

---

$test = new form('name1', 'passw2'); 

// output via property access 
echo $test->username; 
echo $test->password; 

// output via getter methods 
echo $test->getUserName(); 
echo $test->getPassword(); 

// output via the render function of the class 
$test->render(); 

Answer 2

嗨您已經使用_construct應該__contrust(2 underscores)