MySQL在本地和遠程服務器上的不同查詢結果

Question

我通過SQL查詢將MySQL數據庫的副本發送到遠程服務器。

遠程服務器：

Variable_name    Value 
protocol_version   10 
slave_type_conversions  
version      10.0.11-MariaDB 
version_comment    MariaDB Server 
version_compile_machine  x86_64 
version_compile_os   Linux 
version_malloc_library  system 

本地服務器：

Variable_name    Value 
innodb_version    5.6.21 
protocol_version   10 
slave_type_conversions  
version      5.6.21 
version_comment    MySQL Community Server (GPL)  
version_compile_machine  x86 
version_compile_os   Win32 

當我運行下面的查詢，這產生兩種服務器上不同的結果。

select K, S, rn as R, G, V, T, Naam, Club, R1, R2, R3, R4, R5, R6, Totaal 
from (
    select K, S, G, V, T, Naam, Club, R1, R2, R3, R4, R5, R6, R1+R2+R3+R4+R5+R6 as Totaal, 
     @rn := case when @prev = S 
        then @rn + 1 
        else 1 
       end as rn, 
     @prev := S 
    from (
     select K, substr(K,1,1) as S, G, V, T, L.Naam, C.naam as Club, coalesce(R1,0) R1, coalesce(R2,0) R2, coalesce(R3,0) R3, coalesce(R4,0) R4, coalesce(R5,0) R5, coalesce(R6,0) R6 
     from (
      select clubid, naam from club) as C 
       join (select clubid, bondsnummer, if(mv="M", "Dhr.", "Mw.") as G, voorletters as V, tussenvoegsel as T, achternaam as Naam from lid where mv="M") as L on C.clubid=L.clubid 
       join (select bondsnummer, klasse as K, compdnid from deelnemer) as D on L.bondsnummer=D.bondsnummer 
       left join (select compdnid, rondeid, sum(score) as R1 from score where rondeid=1 group by compdnid,rondeid) as R1 on D.compdnid=R1.compdnid 
       left join (select compdnid, sum(score) as R2 from score where rondeid=2 group by compdnid,rondeid) as R2 on R1.compdnid=R2.compdnid 
       left join (select compdnid, sum(score) as R3 from score where rondeid=3 group by compdnid,rondeid) as R3 on R2.compdnid=R3.compdnid 
       left join (select compdnid, sum(score) as R4 from score where rondeid=4 group by compdnid,rondeid) as R4 on R3.compdnid=R4.compdnid 
       left join (select compdnid, sum(score) as R5 from score where rondeid=5 group by compdnid,rondeid) as R5 on R4.compdnid=R5.compdnid 
       left join (select compdnid, sum(score) as R6 from score where rondeid=6 group by compdnid,rondeid) as R6 on R5.compdnid=R6.compdnid 
    ) as S, (select @prev := 0, @rn := 0) as vars 
    order by S, Totaal desc 
) as X 
where Totaal > 0 
limit 0,500 

結果本地服務器上，與@Rn的正確編號爲R：

而且在R列遠程服務器numering出錯：

（請注意，在本地服務器上，記錄不能被編輯，刪除，......而不是遠程。查看前幾列'wij zigen，verwijderen，...'，只是顯得很遙遠。不是我需要這樣做，我只是想知道有什麼區別。）

解釋？如何解決或尋找是什麼原因造成的？

Answer 1

爲什麼要使用子查詢？只要把所有的邏輯在一個查詢：

select K, S, G, V, T, Naam, Club, R1, R2, R3, R4, R5, R6, 
     (R1+R2+R3+R4+R5+R6) as Totaal, 
    @rn := case when @prev = S 
       then @rn + 1 
       else 1 
      end as rn, 
    @prev := S 
from (
    select K, substr(K,1,1) as S, G, V, T, L.Naam, C.naam as Club, coalesce(R1,0) R1, coalesce(R2,0) R2, coalesce(R3,0) R3, coalesce(R4,0) R4, coalesce(R5,0) R5, coalesce(R6,0) R6 
    from (
     select clubid, naam from club) as C 
      join (select clubid, bondsnummer, if(mv="M", "Dhr.", "Mw.") as G, voorletters as V, tussenvoegsel as T, achternaam as Naam from lid where mv="M") as L on C.clubid=L.clubid 
      join (select bondsnummer, klasse as K, compdnid from deelnemer) as D on L.bondsnummer=D.bondsnummer 
      left join (select compdnid, rondeid, sum(score) as R1 from score where rondeid=1 group by compdnid,rondeid) as R1 on D.compdnid=R1.compdnid 
      left join (select compdnid, sum(score) as R2 from score where rondeid=2 group by compdnid,rondeid) as R2 on R1.compdnid=R2.compdnid 
      left join (select compdnid, sum(score) as R3 from score where rondeid=3 group by compdnid,rondeid) as R3 on R2.compdnid=R3.compdnid 
      left join (select compdnid, sum(score) as R4 from score where rondeid=4 group by compdnid,rondeid) as R4 on R3.compdnid=R4.compdnid 
      left join (select compdnid, sum(score) as R5 from score where rondeid=5 group by compdnid,rondeid) as R5 on R4.compdnid=R5.compdnid 
      left join (select compdnid, sum(score) as R6 from score where rondeid=6 group by compdnid,rondeid) as R6 on R5.compdnid=R6.compdnid 
) as S, (select @prev := 0, @rn := 0) as vars 
where (R1+R2+R3+R4+R5+R6) > 0 
order by S, Totaal desc 
limit 0, 500; 

編輯：

您的問題可能沒有實際是limit和order by。這可能是變數。 MySQL確實而不是保證select子句中表達式的求值順序，因此可以在使用prev之前設置它。您可以通過將可變操作組合成單個表達式來解決此問題：

(@rn := if(@prev = S, @rn + 1, 
       if(@prev := S, 1, 1) 
      ) 
    ) as rn 

這實際上可能會解決您的問題。順便說一下，對於SQL代碼，我通常更喜歡case而不是if()作爲條件表達式，因爲case是標準的。但是，變量的使用非常特定於MySQL，並且if()更易於輸入。