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我想這個查詢轉換中迅速:JSON查詢與SWIFT,iOS的
<script>
jQuery.ajax(
{
url: "http://website.net/api/Clients/",
type: 'POST',
headers: {"Token": "Votre token"},
dataType: "json",
data: { "PhoneNumber": phoneNumberValue, "SecretCode": secretCodeValue },
success: function (data) { alert("it worked!") }
});
<script>
我在斯威夫特想這沒有成功:
func submitNumber() {
let session = NSURLSession.sharedSession()
let url = NSURL(string: "http://website.net/api/Clients/")!
let request = NSMutableURLRequest(URL: url)
request.HTTPMethod = "POST」
request.allHTTPHeaderFields = ["Token" : 「myKey」]
let requestDictionary = ["PhoneNumber": 3333333333, "SecretCode": 12345]
request.HTTPBody = try! NSJSONSerialization.dataWithJSONObject(requestDictionary, options: [])
let task = session.dataTaskWithRequest(request) { data, response, error in
if let httpResponse = response as? NSHTTPURLResponse {
let statusCode = httpResponse.statusCode
if (statusCode == 200) {
do {
let json = try NSJSONSerialization.JSONObjectWithData(data!, options:.AllowFragments)
print(json)
}catch {
print(error)
}
} else {
print(「failure」)
}
}
}
task.resume()
}
但它始終是印有 「失敗」,我不知道如何處理它...
我該怎麼辦? 非常感謝!
如果問題是另一個問題的重複,那麼您應該*將其標記爲重複*而不是發佈只是其他答案鏈接的答案。謝謝。 – Moritz
問題是不同的,但他需要的代碼行是相同的。 – NSGangster
將問題標記爲重複也適用於這種情況。 – Moritz