將std :: vector轉換爲char *

-1

我是一名C++學生，致力於使用簡單密碼接收和編碼消息的項目。爲此，程序將每個單詞接受爲一個字符串，將該字符串轉換爲一個字符向量，然後在將每個字符存儲到一個文件中之前對其進行修改。在將編碼消息返回給主函數的行中，我收到此錯誤消息：<無法轉換std::vector<char, std::allocator<char> >' to char *'爲參數1' to char * cipher（char *，int）'。儘管有這個錯誤，程序仍然會運行，但是，只要輸入一個單詞並結束程序，程序就會停止。這是我正在使用的代碼：將std :: vector轉換爲char *

// Cipher.cpp 
// This program accepts a message and encodes it 
// Written by Will Grindle 

#include<iostream.h> 
#include<string.h> 
#include<iomanip.h> 
#include<math.h> 
#include<fstream.h> 
#include<vector.h> 

using namespace std; 

string get_message(); // function prototypes 
char* cipher(char broken[], int length); 

int main() 
{ 
    int index, length; // declare index for vectors 

    string message; // declare string 

    ofstream outfile; // declare filestream 

    outfile.open("MESSAGE.DAT", ios::in); // create file and open it 

    message = get_message(); // use function to retrieve data 

    length = message.length(); // find length of message 

    // declare vector for breaking the strings down 
    vector <char> broken(message.begin(), message.end()); 

    vector <char> encoded(50); // declare vector for encoded message 

    encoded[index] = cipher(broken, length); // initialize encoded to new   message 

    for(index = 0; index <= length - 1; index++)// loop for displaying values 
    { 
     cout << encoded[index] << endl; 
    } 

    if(outfile) // if there is no error with the file 
    { 
     for(index = 0; index <= length - 1; index++) // loop for writing encoded 
     {           // message to file 
     outfile << encoded[index] << endl; 
     cout << "Data written to file." << endl; 
     } 
    } 
    else 
    { 
     cout << "Error opening file." << endl; 
    }   

    outfile.close(); // close file 

    system("pause"); 
    return 0; 
} 

string get_message() 
{ 
    string entry; // declare string 

    cout << "Please enter the word to be entered." << endl; // request entry 
    cin >> entry; // user enters word 

    system ("pause"); 

    return entry; 
} 

char* cipher(char broken[], int length) 
{ 
    char index; // declare index 

    if(broken[index] < 123 && broken[index] > 96) // if characters are lowercase, 
    {            // make them uppercase 
     broken = broken - 32; 
    } 

    for(index = 0; index <= length - 1; index ++) 
    { 
     broken[index] = broken[index] * (2/3); 
     broken[index] = broken[index] - 12; 
     broken[index] = broken[index]^2; 
    } 

    cout << "Message encoded." << endl; 

    system ("pause"); 

    return(broken); 
}

我很樂意提供關於如何使這項工作的任何建議。謝謝！

來源

2016-01-07 Timpanus

嘗試使用char數組，動態分配，因爲您不知道它在編譯時的大小，而不是'vector '您傳遞給'cypher'（稱爲破壞）的第一個參數。這讓我覺得它看起來真的很像作業 – arainone

'#include '???你使用什麼編譯器？ –

在'cypher'中你可以使用'char index'而不需要設置任何值。這將導致未定義的行爲。 – NathanOliver