如何使用PHP從.dat文件中檢索各個數據行？

Question

我無法理解如何從使用PHP的.dat文件中檢索各個數據行（例如名字，年齡，出生年份，性別）。我對網上閱讀的所有內容感到困惑。我需要從.dat文件的文本中獲取每行，併爲每行分配自己的$variable以供稍後用於打印。我到目前爲止。

<?php 
$personalinfo = fopen("personaldata.dat", "r"); 

$firstname = <!-- line one of .dat file -->; 
$age = <!-- line two of .dat file -->; 
$birthyear = <!-- line three of .dat file -->; 
$sex = <!-- line four of .dat file -->; 
$weight = <!-- line five of .dat file -->; 

fclose($personalinfo); 
print("<p> $firstname you are $age years old, born in $birthyear, you are $weight lbs. and $sex.</p>") 
?>  

Answer 1

dat文件格式

有廣泛的格式.dat文件。首先，您必須確定數據在.dat文件中的格式。這聽起來像你說該文件是行分隔（每行代表一個值。）

訪問文件行（文件功能）

PHP可以很容易地獲取文件資源的一行在一個時間，作爲文件函數返回一個數組從文件線形成：

<?php 
$personalinfo = file("personaldata.dat"); 

$firstname = $personalinfo[0]; 
$age = $personalinfo[1]; 
$birthyear = $personalinfo[2]; 
$sex = $personalinfo[3]; 
$weight = $personalinfo[4]; 
print("<p> $firstname you are $age years old, born in $birthyear, you are $weight lbs. and $sex.</p>"); 

訪問文件行（舊學校）

<?php 
$personalinfo = fopen("personaldata.dat", "r"); 
$firstname = fgets($personalinfo); 
$age = fgets($personalinfo); 
$birthyear = fgets($personalinfo); 
$sex = fgets($personalinfo); 
$weight = fgets($personalinfo); 
fclose($personalinfo); 
print("<p> $firstname you are $age years old, born in $birthyear, you are $weight lbs. and $sex.</p>");