在HQL（休眠）中轉換SQL查詢

Question

我有一個使用NOT EXISTS的SQL查詢。如何將此查詢轉換爲HQL？

這是我的方法：

public List<Cage> getByOwnerId(final Long ownerId, final String agriYearId) 
    { 
     return ((List<Cage>)getHibernateTemplate().executeFind(new HibernateCallback(){ 
      public Object doInHibernate(Session session){ 
       String queryString ="select " 
            +"from tbl_cage c, tbl_actor a, tbl_owner o, tbl_inscasecode i, tbl_country co, tbl_inscasecode g , tbl_code cd" 
            +" where " 
            +" i.pk_inscasecodeid = c.FK_CAGETYPE" 
            +" and cd.PK_CODEID=c.FK_CURRENCY " 
            +" and co.PK_COUNTRYID = c.fk_country " 
            +" and G.PK_INSCASECODEID=C.FK_CAGE_INSTALLATIONLOCATION " 
            +" and c.FK_OWNER = o.PK_OWNERID " 
            +" and c.FK_OWNER=:ownerId " 
            +" and " 
            + "not exists (select 1 from tbl_policy, tbl_fishpolicy_cage " 
            +" where c.PK_CAGEID = tbl_fishpolicy_cage.FK_CAGE " 
            +" and tbl_fishpolicy_cage.FK_FISHPOLICY = tbl_policy.PK_POLICYID AND (tbl_policy.FK_CODEID = '018008' OR tbl_policy.FK_CODEID ='018007' OR tbl_policy.FK_CODEID ='018013' OR tbl_policy.FK_CODEID ='018014') " 
            +" and tbl_policy.FK_AGRIYEARID=:agriYearId) " 
            +" and c.PRIMITIVE_COST>0 and c.CAGE_ISDESTROY=0"; 
       Query query = session.createSQLQuery(queryString); 
       List<Cage> returnList; 
       query.setParameter("ownerId", ownerId); 
       query.setParameter("agriYearId",agriYearId); 
       returnList=query.list(); 
       return returnList; 
    }})); 
} 

當我使用List<Object>，我不能在jsp頁面迭代，當我使用List<Cage>我得到這個錯誤：can not cast Object to Cage。

Answer 1

您的查詢不會返回籠子實體的實例。它從這個實體返回單個字段。這樣的查詢的結果是一個列表，每個對象[]包含所有選擇的字段

查詢可以返回多個對象和/或屬性作爲Object類型的數組所以嘗試解析。

試試這個，

returnList = (List<Cage>)session.createSQLQuery(queryString) 
         .setParameter("ownerId", ownerId) 
         .setParameter("agriYearId",agriYearId).list();