反正是有,我可以在此查詢得到整個對象平臺而不只是性質的,我使用波科與EF4:檢索整個對象的加入而不僅僅是性能
var games = (from g in ctx.Games
join p in ctx.Platforms on g.Platform.Id equals p.Id into joinTable
from j in joinTable.DefaultIfEmpty()
select new
{
GameId = g.Id,
Title = g.Title,
PlatformId = j.Id,
PlatformShort = j.Platform_short
});
而不是使用PlatformId的和PlatformShort我只想檢索整個Platform對象(j)。像「平臺= j」
有沒有更好的方式來返回類型集合與迭代通過遊戲第一?
foreach (var g in games)
{
Game game = new Game();
game.Platform = new Platform();
game.Id = g.GameId;
game.Title = g.Title;
game.Platform.Id = g.PlatformId;
game.Platform.Platform_short = g.PlatformShort;
col.Add(game);
}
我嘗試這樣做,而不是:
return ctx.Games.Include("Platform").Take(50).ToList();
,現在我得到了所有100次記錄相同的值。
這裏是SQL:
FROM [dbo].[Games] AS [Extent1]
LEFT OUTER JOIN (SELECT [Extent2].[Id] AS [Id1], [Extent2].[Platform_short] AS [Platform_short], [Extent2].[Platform_long] AS [Platform_long], [Extent2].[Description] AS [Description], [Extent2].[Image] AS [Image], [Extent2].[CreatedDate] AS [CreatedDate1], [Extent2].[ModifiedDate] AS [ModifiedDate1]
FROM [dbo].[Platforms] AS [Extent2]
LEFT OUTER JOIN [dbo].[Games] AS [Extent3] ON [Extent2].[Id] = [Extent3].[PlatformId]) AS [Join1] ON [Extent1].[PlatformId] = [Join1].[Id1] LEFT OUTER JOIN (SELECT [Extent4].[Id] AS [Id3], [Extent5].[Id] AS [Id2]
FROM [dbo].[Platforms] AS [Extent4]
LEFT OUTER JOIN [dbo].[Games] AS [Extent5] ON [Extent4].[Id] = [Extent5].[PlatformId]) AS [Join3] ON [Extent1].[PlatformId] = [Join3].[Id3]
某處有問題,你的應用程序,因爲使用'平臺= j'應該工作。 – 2011-03-15 21:12:18