xcode做一個隨機的方法

Question

嗨，每一個我是法國人，如此scuse我的我的英語。那麼我想要做的是每一秒我都會在四種方法之間做一個隨機方法。我怎麼能這樣做？

Answer 1

某處你需要啓動定時器

[NSTimer scheduledTimerWithTimeInterval:1 target:self selector:@selector(randomMethod:) userInfo:nil repeats:YES]; 

然後實現將被調用的方法：

-(void)randomMethod:(NSTimer *)timer { 

    if (shouldStop) { 
     [timer invalidate]; 
     return; 
    } 

    int rand = arc4random() % 4; 

    switch (rand) { 
     case 0: 
      [self method0]; 
      break; 
     case 1: 
      [self method1]; 
      break; 
     case 2: 
      [self method2]; 
      break; 
     case 3: 
      [self method3]; 
      break; 
    } 
} 

再後來，在某些時候，如果你想停止它，設置shouldStop爲true。

Answer 2

你想要一個1和4之間的隨機整數，然後case語句來執行相應的選擇器，對不對？

Answer 3

4個字符串（您的方法的名稱）的數組，在0和3之間生成隨機int，然後使用NSSelectorFromString來調用。

Answer 4

例如，你有四種方法：

//put them on array as strings 
NSArray *arrayOfSelectors = [NSArray arrayWithObjects:@"eat", @"drink", @"run", @"sleep", nil]; 

//generate a random number based on the number of selectors inside the array 
int randomNumber = arc4random()%arrayOfSelectors.count; 

//call the method 
//assumes that someObject really implement the methods inside the array, else your app will crash 
[someObject performSelector:NSSelectorFromString([arrayOfSelectors objectAtIndex:randomNumber])]; 

1. - （無效）吃;
2. - （void）drink;
3. - （void）run;
4. - （void）sleep;

Answer 5

首先創建定時器：

NSTimer *t = [NSTimer scheduledTimerWithTimeInterval: 1.0 
               target: self 
              selector:@selector(selectorSwitcher:) 
              userInfo: nil repeats:YES]; 
NSRunLoop *runner = [NSRunLoop currentRunLoop]; 
[runner addTimer:t forMode: NSDefaultRunLoopMode]; 

然後實現切換器：

-(void)selectorSwitcher:(NSTimer *)timer { 

    int randomNumber = 1+ arc4random() %(4); 
    switch (randomNumber) { 
     case 1: 
      [self selector1]; 
      break; 
     case 2: 
      [self selector2]; 
      break; 
     case 3: 
      [self selector3]; 
      break; 
     case 4: 
      [self selector4]; 
      break; 

     default: 
      break; 
    } 

}