什麼RegEx會清理這組輸入？

Question

我試圖找出一個正則表達式，將符合下列條件：

.../string-with-no-spaces - >string-with-no-spaces

或

string-with-no-spaces:... - >string-with-no-spaces

或

.../string-with-no-spaces:... - >string-with-no-spaces

那裏......可以是任何東西在這些例子字符串：

example.com:8080/string-with-no-spaces:latest 
string-with-no-spaces:latest 
example.com:8080/string-with-no-spaces 
string-with-no-spaces 

和獎金將

http://example.com:8080/string-with-no-spaces:latest 

和所有將匹配string-with-no-spaces。

是否有可能爲一個單一的正則表達式來涵蓋所有這些情況？

到目前爲止，我已經儘可能/\/.+(?=:)/得到但這不僅包括斜槓，但只適用於情況3.任何想法？

編輯：我還想說，我使用Node.js的，所以理想的解決方案應該通過所有這些：https://jsfiddle.net/ys0znLef/

Answer 1

如何：

(?:.*/)?([^/:\s]+)(?::.*|$) 

Answer 2

下面是我的表達得到...只是試圖調整使用斜線，但不包括它。

更新結果JS

\S([a-zA-Z0-9.:/\-]+)\S 
//works on regexr, regex storm, & regex101 - tested with a local html file to confirm JS matches strings 

var re = /\S([a-zA-Z0-9.:/\-]+)\S/; 

Answer 3

使用特定的正則表達式模式和String.match功能考慮以下解決方案工作：

var re = /(?:[/]|^)([^/:.]+?)(?:[:][^/]|$)/, 
    // (?:[/]|^) - passive group, checks if the needed string is preceded by '/' or is at start of the text 
    // (?:[:][^/]|$) - passive group, checks if the needed string is followed by ':' or is at the end of the text 
    searchString = function(str){ 
     var result = str.match(re); 
     return result[1]; 
    }; 

console.log(searchString("example.com:8080/string-with-no-spaces")); 
console.log(searchString("string-with-no-spaces:latest")); 
console.log(searchString("string-with-no-spaces")); 
console.log(searchString("http://example.com:8080/string-with-no-spaces:latest")); 

所有情況下的輸出結果爲string-with-no-spaces