我正在運行一個小的servlet程序,但它沒有給出預期的輸出。Servlet程序運行不正常
Servletfile.java
public class Servletfile extends HttpServlet {
private static final long serialVersionUID = 1L;
protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
response.setContentType("text/ html");
PrintWriter out= response.getWriter();
String abc = request.getParameter("name");
out.print("name="+abc);
}
protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
}
}
的index.html
<!DOCTYPE html>
<html>
<head>
<meta charset="ISO-8859-1">
<title>Insert title here</title>
</head>
<body>
<Form action= "welcome" method="get">
Enter Name :<input type = "text" name="name"><br>
<input type = "Submit" value= "login">
</Form>
</body>
</html>
的web.xml
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" id="WebApp_ID" version="2.5">
<display-name>Practice</display-name>
<welcome-file-list>
<welcome-file>index.html</welcome-file>
<welcome-file>index.htm</welcome-file>
<welcome-file>index.jsp</welcome-file>
<welcome-file>default.html</welcome-file>
<welcome-file>default.htm</welcome-file>
<welcome-file>default.jsp</welcome-file>
</welcome-file-list>
<servlet>
<description></description>
<display-name>Servletfile</display-name>
<servlet-name>Servletfile</servlet-name>
<servlet-class>code.Servletfile</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>Servletfile</servlet-name>
<url-pattern>/Servletfile</url-pattern>
</servlet-mapping>
</web-app>
上執行的代碼,它顯示index.html頁面,但如果我輸入任何名稱作爲輸入,然後它給404頁找不到錯誤。如果我單獨運行servlet程序,它將name = null作爲輸出。你能給我一些建議嗎?
請同時發佈你的'web.xml'文件。這對我們能夠幫助你至關重要。 – 2015-03-03 07:07:07
它看起來像你的表單沒有觸及servlet,考慮到你的行爲只是簡單的「welcome」,但web.xml文件將告訴所有人,這並不奇怪。 – 2015-03-03 07:08:49
我已經添加了web.xml文件,請看看 – Archana 2015-03-03 07:13:21