試圖讓球從數組組件中反彈回來？ （不能想到一個更好的詞）C＃

Question

我有一個球根據需要從槳和牆壁反彈，然後我通過draw.Rectangle工具添加了一個單獨的磚，並有球從這反彈，然後改變它的顏色但無法阻止任何進一步的碰撞。 我正在使用一個數組作爲我的磚，因爲我可以有很多，可以打他們後真或假

我的問題是，我試圖讓球與所述陣列磚碰撞，但不能爲即使盡可能多地使用google搜索，我的生活也會發現它。這裏是我的代碼片斷，我認爲「應該」的碰撞

for (int i = 0; 1 < brickLive.Length; i++) 
       if ((y == brickLocation[i, 0]) && (x >= brickLocation[0, i]) && (x <= (brickLocation[0, i] + 60))) 
        yChange = -yChange; 

我的理解這個工作代碼爲說的價值我檢查，如果球COORDS是在一個磚的位置的參數。如果是那麼改變方向。 與它運行良好，直到我開始遊戲當前的代碼（我點擊插入按鈕，使反彈按鈕工作）

這裏是我的全部代碼

using System; 
using System.Collections.Generic; 
using System.ComponentModel; 
using System.Data; 
using System.Drawing; 
using System.Linq; 
using System.Text; 
using System.Threading.Tasks; 
using System.Windows.Forms; 

namespace Breakout 
{ 
    public partial class Form1 : Form 
    { 

     private int x, y, x2, y2; 
     private int xChange, yChange; 

     int bat, batX, batXX, mouseX; 

     private Graphics paper; 
     private Pen pen, pen2, pen3; 

     private Pen brkpen; 

     private Random ranNum; 

     int brkLength = 60; 
     int brkHeight = 20; 
    int[,] brickLocation = { { 0, 100 }, { 61, 100 }, { 122, 100 } }; 
    bool[] brickLive = { true, true, true }; 


    public Form1() 
    { 
     InitializeComponent(); 

     paper = picDisplayBat.CreateGraphics(); 
     pen = new Pen(Color.Red); 
     pen.Width = 10; 
     ranNum = new Random(); 

     paper = picDisplayBat.CreateGraphics(); 
     pen = new Pen(Color.Blue); 
     pen.Width = 3; 

     paper = picDisplayBat.CreateGraphics(); 
     pen2 = new Pen(Color.Red); 
     pen.Width = 3; 

     picDisplayBat.MouseMove += new 
     System.Windows.Forms.MouseEventHandler(picDraw_MouseMove); 

     paper = picDisplayBat.CreateGraphics(); 
     brkpen = new Pen(Color.Black); 
     brkpen.Width = 3; 


     //paper = picDisplayBat.CreateGraphics(); 
     //pen3 = new Pen(Color.Green); 
     //pen3.Width = 5; 
} 


    private void picDraw_MouseMove(object sender, System.Windows.Forms.MouseEventArgs e)       //DRAWING THE BAT TO MOVE WITH MOUSE 
    { 
     //paper.Clear(Color.White); 
     mouseX = e.X; 
    } 


    private void btnInsert_Click_1(object sender, EventArgs e) 
    { 
     { 
      btnBounce.Visible = true; 
     } 
    } 

    private void btnBounce_Click_1(object sender, EventArgs e) 
    { 
     { 

      timer1.Interval = 25; 
      timer1.Enabled = true; 

      x = ranNum.Next(1, picDisplayBat.Height); 
      y = ranNum.Next(1, picDisplayBat.Width); 
      xChange = ranNum.Next(1, 10); yChange = ranNum.Next(1, 10); 


      for (int i = 0; i < brickLive.Length; i++) 
      { 
       paper.DrawRectangle(brkpen, brickLocation[i, 0], brickLocation[i, 1], brkLength, brkHeight); 


      } 

     } 
    } 

    private void timer1_Tick(object sender, EventArgs e) 
    { 
     { 

      x = x + xChange; 
      y = y + yChange; 
      if (x >= picDisplayBat.Width) 
       xChange = -xChange; 

      if (y >= picDisplayBat.Height) 
       yChange = -yChange; 

      if (x <= 0) 
       xChange = -xChange; 

      if (y <= 0) 
       yChange = -yChange; 

      if ((y > picDisplayBat.Height - 20) && (x >= batX + 10) && (x <= batX + 50)) 
       yChange = -yChange; 

      if ((y < picDisplayBat.Height - 295) && (x >= batX + 10) && (x <= batX + 50)) 
       yChange = -yChange; 

      for (int i = 0; 1 < brickLive.Length; i++) 
       if ((y == brickLocation[i, 0]) && (x >= brickLocation[0, i]) && (x <= (brickLocation[0, i] + 60))) 
        yChange = -yChange; 



       paper.Clear(Color.White); 
      paper.DrawRectangle(pen, mouseX + 10, picDisplayBat.Height - 20, 50, 10);   //bat 1 
      paper.DrawEllipse(pen, x, y, 10, 10);            //ball 
      paper.DrawRectangle(pen2, mouseX + 10, picDisplayBat.Height - 295, 50, 10);  //bat2 
      //paper.DrawRectangle(pen3, x2, y2, 60, 10); 
      bat = mouseX; 
      batX = mouseX; 
      batXX = mouseX; 

      for (int i = 0; i < brickLive.Length; i++) 
      { 
       paper.DrawRectangle(brkpen, brickLocation[i, 0], brickLocation[i, 1], brkLength, brkHeight); 


      } 
     } 
    } 

    private void btnExit_Click(object sender, EventArgs e) 
    { 

    Environment.Exit(0); 

    } 

    private void btnStop_Click(object sender, EventArgs e) 
    { 


      timer1.Enabled = false; 
      paper.Clear(Color.White); 

     } 

} 

}

Answer 1

這看起來不對我。

if ((y == brickLocation[i, 0]) && (x >= brickLocation[0, i]) && (x <= (brickLocation[0, i] + 60)))

在我看來，你應該始終有[i, ...爲磚陣列的位置，所以無論是[i, 0]針對用於垂直分量的水平分量和[i, 1]測試。