0
我想告訴(網友:....),但我不知道路徑的用戶。如何在列表視圖中選擇用戶顯示。請看看我的代碼,並幫助我
public class ListUserRoom extends AppCompatActivity {
private ListView listView;
List<Member> members = new ArrayList<>();
private DatabaseReference mDatabase = FirebaseDatabase.getInstance().getReference();
private String keyOfRoom = "";
private String keyOfMember = "";
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_list_user_room);
createListUser();
}
private void createListUser() {
listView = (ListView)findViewById(R.id.listView);
listView.setAdapter(new ListUserRoom.ImageAdapter(this));
Intent getData = getIntent();
if(getData != null){
keyOfRoom = getData.getExtras().getString("key" , "");
}
getData = getIntent();
if(getData != null){
keyOfMember = getData.getExtras().getString("keymember" , "");
}
mDatabase = FirebaseDatabase.getInstance().getReference()
.child("AllRoom").child(keyOfRoom)
.child("Member").child(keyOfMember)
.child("User");
mDatabase.addValueEventListener(new ValueEventListener() {
@Override
public void onDataChange(DataSnapshot dataSnapshot) {
Set<String> set = new HashSet<String>();
Iterator i = dataSnapshot.getChildren().iterator();
dataSnapshot.getValue();
while (i.hasNext()){
DataSnapshot data = (DataSnapshot)i.next();
Member member = data.getValue(Member.class);
member.setKey(data.getKey());
members.add(member);
}
}
@Override
public void onCancelled(DatabaseError databaseError) {
}
});
}
如何選擇表用戶:(所有)和Member.class其模型顯示LISTUSER(私人字符串鍵,用戶)設置,獲得密鑰的用戶
你可以發佈你的Member.java類嗎?行! – wnieves19
行!兄弟編輯完成謝謝你的幫助! @ wnieves19 – ThLez