倒計時4周（一週一週）回到python/django

有人可以知道我可以做什麼倒數4週迴到給定的一年，然後計算每週的start_date和end_date？倒計時4周（一週一週）回到python/django

這是我現在有：從這個

def FourWeeks(year, week): 
    d = date(year, 1, 1) 
    delta_days = d.isoweekday() - 1 
    fourweekback = [week - x for x in range(4)] 
    for delta_weeks in fourweekback: 
     delta = timedelta(days=-delta_days, weeks=delta_weeks) 
     weekbeg = datetime.datetime.combine(d, datetime.time(00, 00, 01)) + delta 
     delta2 = timedelta(days=6-delta_days, weeks=delta_weeks) 
     weekend = datetime.datetime.combine(d, datetime.time(23, 59, 59)) + delta2 
    return (fourweekback, weekbeg, weekend)

輸出：

FourWeeks(2013, 44) 
    ([40, 39, 38, 37], datetime.datetime(2013, 10, 7, 0, 0, 1), datetime.datetime(2013, 10, 13, 23, 59, 59)) 
    ([40, 39, 38, 37], datetime.datetime(2013, 9, 30, 0, 0, 1), datetime.datetime(2013, 10, 6, 23, 59, 59)) 
    ([40, 39, 38, 37], datetime.datetime(2013, 9, 23, 0, 0, 1), datetime.datetime(2013, 9, 29, 23, 59, 59)) 
    ([40, 39, 38, 37], datetime.datetime(2013, 9, 16, 0, 0, 1), datetime.datetime(2013, 9, 22, 23, 59, 59)) 
    ([40, 39, 38, 37], datetime.datetime(2013, 9, 16, 0, 0, 1), datetime.datetime(2013, 9, 22, 23, 59, 59))

，這就是我想實現：

FourWeeks(2013, 44) 
    (44, datetime.datetime(2013, 10, 28, 0, 0, 1), datetime.datetime(2013, 11, 3, 23, 59, 59)) 
    (39, datetime.datetime(2013, 9, 23, 0, 0, 1), datetime.datetime(2013, 9, 29, 23, 59, 59)) 
    (38, datetime.datetime(2013, 9, 16, 0, 0, 1), datetime.datetime(2013, 9, 22, 23, 59, 59)) 
    (37, datetime.datetime(2013, 9, 9, 0, 0, 1), datetime.datetime(2013, 9, 15, 23, 59, 59))

在下一步我喜歡用weekbeg做個查詢，週末

cursor.execute("SELECT * FROM event WHERE datetime BETWEEN %s AND %s, [weekbeg, weekend])

任何想法我可以做到這一點？

來源

2013-12-07 Robert

根據什麼DBMS你'使用你可以將計算移動到SQL中...像這樣：http://stackoverflow.com/questions/7391718/select-records-from-one-week-previous-in-mysql –

此外 - 你的日期不要如果你定義了一個星期到底是什麼，那麼它會很有幫助（從特定的日子等開始......）我看不出你是如何得到10月28日在那裏 –

我會說我的一週開始星期一和結束星期天 – Robert

您應該能夠適應以下（注意它使用的第三方dateutil這是易於安裝通過PIP & CO）：

from dateutil.relativedelta import relativedelta 
from dateutil.rrule import rrule, WEEKLY, MO, SU 
from datetime import datetime, timedelta 

def four_weeks(year, week): 
    end = datetime(year, 1, 1) + relativedelta(weeks=week-1, weekday=SU) 
    start = end - relativedelta(weeks=4, weekday=MO) 
    mint, maxt = datetime.min.time(), datetime.max.time() 
    for dt in rrule(WEEKLY, start, count=4): 
     yield dt.combine(dt, mint), dt.combine(dt + timedelta(days=6), maxt) 

for start, end in four_weeks(2013, 44): 
    print start, '->', end

輸出：

2013-10-07 00:00:00 -> 2013-10-13 23:59:59.999999 
2013-10-14 00:00:00 -> 2013-10-20 23:59:59.999999 
2013-10-21 00:00:00 -> 2013-10-27 23:59:59.999999 
2013-10-28 00:00:00 -> 2013-11-03 23:59:59.999999

來源

2013-12-07 18:45:01

謝謝，這就是我一直在尋找。 – Robert

倒計時4周（一週一週）回到python/django

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