第5周到第52周，然後第1周到第4周共計52周

Question

我做了一個PHP函數，計算從現在到52周的週數，然後從第1周開始再向左數週。

我想知道是否有更簡單的方法來做到這一點，或者我做出了正確的功能。

這是我的代碼：

function weeks($start_week) 
       { 

        $start_week  = str_replace("0", "", $start_week); // from week 1 tot 9 remove the zero's. 
        $offset_week = $start_week - 1; // when the loop reach week 52, start with new weeks minus 1 
        $last_week  = 52; // Last week of the year 

        $aantal_weken = 52; // # of weeks in a year 

        for($start_week; $start_week <= $aantal_weken; $start_week++) 
        { 
         echo $start_week.", "; 

         if($start_week == $last_week) 
         { 
          $new_weeks = 1; // when we reach week 52, set a new variable tot first week of the year 

          for($new_weeks; $new_weeks <= $offset_week; $new_weeks++) 
          { 
           echo $new_weeks.", ";       
          } 
         } 
        } 

        return $start_week; 
       } 

       $date = date("W"); 
       weeks($date); 

輸出：

4，5，6，7，8，9，10，11，12，13，14，15，16，17， 18，19,20,21,22,23,24,25,26,27,28,29,30,31,32,33,34,35,36,37,38,39,40,41,42， 43，44，45，46，47，48，49，50，51，52，1，2，3，

Answer 1

返回陣列周範圍：

function weeks($start_week) { 
    $last_week = date_format(date_create('December 28th'), 'W'); 
    $range = range(1, $last_week); 
    return array_merge(
     array_slice($range, $start_week - 1), 
     array_slice($range, 0, $start_week - 1) 
    ); 
} 

demo

Answer 2

您的問題實際上與日期無關。它只與數學有關。試試下面的代碼：

function weeks($start_week) { 
    $arr = array(); 
    for ($i = 0; $i < 52; $i++) { 
     $arr[] = ($i + $start_week - 1) % 52 + 1; 
    } 
    return implode(', ', $arr); 
} 
echo weeks(4); 

Answer 3

function weeks($start_week) 
{ 
    $start_week  = str_replace("0", "", $start_week); // from week 1 tot 9 remove the zero's. 
    $offset_week = $start_week - 1; // when the loop reach week 52, start with new weeks minus 1 
    $last_week  = 52; // Last week of the year 
    $aantal_weken = 52; // # of weeks in a year 

    for($start_week; $start_week <= $aantal_weken; $start_week++) 
    { 
     echo $start_week.", "; 

     if($start_week == $last_week) 
     { 
      $new_weeks = 1; // when we reach week 52, set a new variable tot first week of the year 

      for($new_weeks; $new_weeks <= $offset_week; $new_weeks++) 
      { 
       echo $new_weeks.", ";       
      } 
     } 
    } 

    return $start_week; 
} 

$date = date("W"); 
weeks($date);